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svet-max [94.6K]
3 years ago
5

Given that f(x)= 3x^2-5x +3 and g(x)= -x^2 + 17 find (f-g) (x)

Mathematics
1 answer:
Sliva [168]3 years ago
3 0
4x^2-5x-14 is your answer :)
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Yellow Cab Taxi charges a $1.75 flat rate for a ride in the cab. In addition to that, they charge $0.45 per mile. Katie has no m
Katena32 [7]

Answer:

.45x + 1.75 < 12

.45x < 10.25

x < 22.7 miles

8 0
3 years ago
Which of the following quartic functions has x=-1 and x=-2 as its only two real zeros
Brums [2.3K]
Quartic is 4th degree
the factors of an equation with roots r1,r2 is
(x-r1)(x-r2)
4th degree
it could be
(x-r1)¹(x-r2)³ or
(x-r1)²(x-r2)² or
(x-r1)³(x-r2)¹


roots or zeroes at x=-1 and x=-2
(x-(-1)) and (x-(-2))
(x+1) and (x+2)

the function could be factored into
(x+1)¹(x+2)³ or
(x+1)²(x+2)² or
(x+1)³(x+2)¹

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x⁴+7x³+18x²+20x+9 or
x⁴+6x³+13x²+12x+4 or
x⁴+5x³+9x²+7x+2
one of those is the answer

4 0
3 years ago
10. Solve the following equations<br><br> a) Cos Ɵ = -1/2<br><br><br><br><br> b) -18 Sin Ɵ + 9 = 0
Olenka [21]

Answer:

what is cos and sin ?

Step-by-step explanation:

4 0
2 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
Find the volume of the cylinder
posledela

Answer:

I nk a ......................

8 0
3 years ago
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