Answer:
Poor Alex, I know how they feel, I got a dog myself.
The amount of time between
11:41 pm to 12:09 am is
19 minutes (to 12 am, 60 minutes to next hour) + 9
which is 28 minutes for the first dog barking session
the second time is 35 minutes,
using same method as before.
adding the two separte barking sessions we get
35+28= 63 minutes
which is equivelant to 1 hour and 3 minutes.
In conclusion the dog barks for 1 hour and 3 minutes in total.
Add
5
5
to both sides of the equation.
√
2
x
+
13
=
x
+
5
2
x
+
13
=
x
+
5
To remove the radical on the left side of the equation, square both sides of the equation.
(
√
2
x
+
13
)
2
=
(
x
+
5
)
2
(
2
x
+
13
)
2
=
(
x
+
5
)
2
Simplify each side of the equation.
2
x
+
13
=
x
2
+
10
x
+
25
2
x
+
13
=
x
2
+
10
x
+
25
Solve for
x
x
.
x
=
−
2
,
−
6
x
=
-
2
,
-
6
Exclude the solutions that do not make
√
2
x
+
13
−
5
=
x
2
x
+
13
-
5
=
x
true.
x
=
−
2
Answer:
3000×(1.0423)cubed = 3403.64-3000=403.64
Answer:
<h3>
The second: f(-5) = 2</h3>
Step-by-step explanation:
x = -5
-5 < -4 and if x<-4 then f(x) = - 2x - 8
so:
f(-5) = - 2(-5) - 8 = 10 - 8 = 2
Answer:
Second puck travels farther
Step-by-step explanation:
Maximum height of first puck = 3 feet
The height of a second hockey puck is modeled by:
To find maximum height of second puck
Equate the derivative equals to 0
0.15-0.002x=0
75 = x
At x = 75
So, The maximum height of second puck is greater than first puck
So, Second puck travels farther
