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atroni [7]
3 years ago
8

Quadrilateral ACEG≅ Quadrilateral MNPR

Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0
<span>CE≅NP. I've done the test before.</span>
LenaWriter [7]3 years ago
4 0

Answer:

CE¯¯¯¯¯≅NP¯¯¯¯¯¯

Step-by-step explanation:

I am taking the test it is a 100% right! ;)

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The graph shows the relationship between the number of granola bars and amount of calories per bar.
castortr0y [4]

part a y= x × 100

Step-by-step explanation:

1 bar is 100 calories so you would times it by 100 for every bar

5 0
3 years ago
Which table goes with the graph?
Fudgin [204]

Answer:

74

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
At their​ family's pizzeria, Dave makes 6 pizzas in the first hour it is open and 3 pizzas each hour after that. Lauren makes 11
Nady [450]

Answer:

47 pizzas

Step-by-step explanation:

Dave makes 6 pizzas in the first hour it is open and 3 pizzas each hour after that.

If the number of hours after the first hour  is represented as x, then the number of pizzas he makes after x hours is:

6 + 3x

Lauren makes 11 pizzas in the first hour and 3 pizzas each hour after that. Then:

11 + 3x

The pizzeria is open for 6 hours in all, that is, 5 hours after the first hour.

This means that:

x = 5

The total amount of pizzas that Dave and Lauren make is:

6 + 3x + 11 + 3x

=> 17 + 6x

Therefore, the total amount of pizza they make 5 hours after the first hour is:

17 + 6(5) = 17 + 30 = 47 pizzas

3 0
3 years ago
How many times larger is a centigram than a milligram
Sauron [17]

Answer:

centi = a unit / 100

milli = a unit / 1000

centiX = 10 milliX

8 0
3 years ago
The assumptions made are: The gas molecules from Caesar's last breath are now evenly dispersed in the atmosphere. The atmosphere
Dovator [93]

Answer:

2.6\times 10^{19}m^{3}

Step-by-step explanation:

we have given thickness of atmosphere =50 km

radius of earth =6400 km

average temperature of atmosphere=15°C

Average pressure of atmosphere= 0.20 atm

we have to calculate the volume of atmosphere

so the we have to calculate the volume of atmosphere = ( volume of earth +atmosphere) - volume of earth

volume of atmosphere =\frac{4}{3}\times\pi \times \left ( 6400+50 \right )^{3}-\frac{4}{3}\times \pi\times 6400^3

=2.6\times 10^{19}m^{3}

6 0
3 years ago
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