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3 years ago

HELP PLEASE!!! I HAVE NO IDEA WHAT IM DOING

Mathematics

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

Step-by-step explanation:

We require to find the cube root (n = 3) pf a = 1000, that is

the root is

$\sqrt[3]{1000}$ = 10 ( since 10 × 10 × 10 = 1000 )

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Can you guys pls help me with this

insens350 [35]

1.probability of not rolling a factor 5 =25/36

2.probability of rolling a difference of 3=1/6

3.probability of rolling the product of 12=1/9

4.probability of rolling the product 6=1/9

5.probability of rolling factors of 2 on second die=1/3

6.probability of not rolling multiples of 4 on both die=25/36

7.probability of not rolling a sum of 5=8/9

8.probability of rolling a difference 1=10/36

9.probability of not rolling factors of 6 on both die=4/6

10.probability of not rolling prime numbers on both dice=1/4

Step-by-step explanation:

To solve all possible probabilities, we have to find out the sample space of the experiment of rolling two dice simultaneously.

Sample space S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)}

{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)}

{(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)}

{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)}

{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)}

{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

probability of not rolling a factor 5

possible set={(1,1),...(1,4),(1,6),(2,1),....(2,4),(2,6),(3,1)......(3,4),(3,6),(4,1)...(4,4),(4,6),(6,1)....(6,4),(6,6)}

number of events n(E)=25

p(not a factor of 5)=n(E)/n(S)=25/36

probability of rolling a difference of 3

E={(1,4),(2,5),(3,6),(4,1),(5,2),(6,3)}

number of events=6

P(difference of 3)=n(E)/n(S)=6/36=1/6

probability of rolling the product of 12

E={(2,6),(3,4),(4,3),(6,2)}

n(E)=4

P(E)=n(E)/n(S)=4/36=1/9

probability of rolling the product 6

E={(1,6),(2,3),(3,2),(6,1)}

n(E)=4

P(E)=n(E)/n(S)=4/36=1/9

probability of rolling factors of 2 on second die

E={(1,1),(1,2),(2,1),(2,2),(3,1),(3,2),(4,1),(4,2),(5,1),(5,2),(6,1),(6,2)}

n(E)=12

P(E)=n(E)/n(S)=12/36=1/3

probability of not rolling multiples of 4 on both die

E={(1,1),(1,2),(1,3),(1,5),(1,6),(2,1),(2,2),(2,3),(2,5),(2,6),(3,1),(3,2),(3,3),(3,5),(3,6),(5,1),(5,2),(5,3),(5,5),(5,6),(6,1),(6,2),(6,3),(6,5),(6,6)}

n(E)=25

P(E)=n(E)/n(S)=25/36

probability of not rolling a sum of 5

E={(1,1),(1,2),(1,3),(1,5),(1,6),(2,1),(2,2),(2,4),(2,5),(2,6),(3,1),(3,3),(3,4),(3,5),(3,6),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),......(5,6),(6,1),......(6,6)

n(E)=32

P(E)=n(E)/n(S)=32/36=8/9

probability of rolling a difference 1

E={(1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5)}

n(E)=10

P(E)=n(E)/n(S)=10/36

probability of not rolling factors of 6 on both die

E={(4,4),(4,5),(5,4),(5,5)}

n(E)=4

P(E)=n(E)/n(S)=4/6

probability of rolling prime numbers on both dice

E={(2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)}

n(E)=9

P(E)=n(E)/n(S)=9/36=1/4

3 0

3 years ago

How does the mean of the data set below change if each value is increased by 8?

jenyasd209 [6]

Suppose our data set is:
2,4,6,8
the mean of the above data is:
(2+4+6+8)/4=20/4=5

Increasing the above value by 8
10,12,14,16
the mean will be:
(10+12+14+16)/4
=52/4
=13
The difference in the two mean values i
13-5=8
Thus we conclude that if we increase our values by 8, the mean increases by 8

7 0

3 years ago

Which constant term should be used to complete the square? x^2-5x+__=7

lora16 [44]

The constant term should be (-5/2)^2 or (5/2)^2 or 25/4. This constant term comes from taking the coefficient on the x^1 term, halving it, and then squaring it.

7 0

3 years ago

An actor invests some money at 7%, and $24000 more than four times the amount at 8%. The total annual interest earned from the i

natita [175]

Answer:

$70,000 at 7%
$304,000 at 8%

Step-by-step explanation:

Given:

Total interest earned on two investments is $29,220.

An amount is invested at 7%.

$24,000 more than 4 times that amount is invested at 8%.

Find:

The amount invested at each rate.

Solution:

Our strategy will be to define a variable representing the amount invested at 7%, use that variable to write an expression for the amount invested at 8%, then write an equation for the total return on the investments.

Let x represent the amount invested at 7%. Then (24,000+4x) will be the amount invested at 8%. The total interest earned will be ...

interest on 7% account + interest on 8% account = total interest

0.07x + 0.08(24000+4x) = 29220

0.39x + 1920 = 29220 . . . . . . . . . . . simplify

0.39x = 27300 . . . . . . . . . . . . . . . . . .subtract 1920

x = 27300/0.39 = 70000 . . . . . . . . . divide by the coefficient of x

24,000 +4x = 24,000 +280,000 = 304,000 . . . . amount invested at 8%

He invested $70,000 at 7% and $304,000 at 8%.

Check

The answer must satisfy ...

7% interest + 8% interest = 29,220

0.07×70,000 +0.08×304,000 = 4,900 +24,320 = 29,220 . . . . as required

_____

Comment on 6-step method

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Identify the given information (Given)
Identify the question you are asked to answer (Find)
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6 0

3 years ago

How do you write 0.326 in word form?

ryzh [129]

Three hundred twenty-six thousandths.

8 0

3 years ago