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FromTheMoon [43]
3 years ago
7

P viuen

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
Hello what do you exactly need help for
You might be interested in
2. John and Jen went to the farmers market to buy fruit. John bought 3 boxes of oranges and 9 boxes of cherries for $78. Jen bou
jenyasd209 [6]

Answer:

Let the cost of orange be X and cost of cherry be y

3x + 9y = 78

8x + 4y = 58

Solving equation using elimination method

multiplying eq 1 with 8 and eq 2 with 3

8(3x + 9y ) = 78(8)

3( 8x + 4y) = 3(58)

24x + 72 y = 624

24x + 12y = 174

subtracting,

60 y = 450

y = 7.5

3x + 9(7.5) = 78

3x + 67.5 = 78

3x = 78 - 67.5

3x = 10.5

x = 3.5

<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
7 0
2 years ago
A toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.
Vinil7 [7]

Answer:

s=p−(p⋅d) .      0.75p

Step-by-step explanation:

6 0
3 years ago
After learning the theoretical probability of a two sided coin landing on any one side, students work in groups to flip the coin
Bumek [7]
The answer c, because they got 9 out of 15 flips being heads. This probability is 0.6. The other answers are not accurate.
3 0
3 years ago
At silver Gym, membership is $45 per month, and personal training sessions are $25 each. At fit factor, membership is $75 per mo
tiny-mole [99]
Let S represent the cost of use of Silver Gym for a month.
Let F represent the cost of use of Fit Factor for a month.
Let T represent the number of training sessions used in the month.

S = 45 +25T
F = 75 +15T

We want to find T so the costs are equal.
.. S = F
.. 45 +25T = 75 +15T
.. 10T = 30 . . . . . . . . . subtract 45+15T
.. T = 3 . . . . . . . . . . . . divide by 10

Sarah would have to buy 3 training sessions to make the cost at the two gyms equal.
4 0
4 years ago
Please help I don’t understand
charle [14.2K]

Answer:

\huge\boxed{\sf

Step-by-step explanation:

Since AB is parallel to CD,

∠h = 80°    (alternate angles)

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
Read 2 more answers
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