Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
C. The Triangle Inequality Theorem States that any two sides of a triangle must be greater than the third side. It cannot be A because 35+40= 75, which is not greater than 75. It cannot be B because 40+30= 70, which is not greater than 75. It cannot be D because 35+40= 75, which is not greater than 80. It is C because 40+30= 70, which is greater than 65.
Answer:
L(18, 20)
Step-by-step explanation:
In JL, K is the midpoint. The coordinates of J are (2, 2), and the
coordinates of K are (10, 11). What are the coordinates of L?
Solution:
If O(x, y) is the midpoint between two points A(
) and B(
). The equation to determine the location of O is given by:

Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let (
) be the coordinate of L. Therefore:


Therefore L = (18, 20)
2-5/8-6/8=16/8-5/8-6/8=5/8 pizza slices left
3/8+7/8=10/8=1 2/8 pizza slices altogether
hope it helps:))
Answer:

Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a
, creating right triangles
and
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where
is the hypotenuse, or the longest side, of the triangle
Thus, we have:

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 