Answer:
1:2
is your answer
Step-by-step explanation:
Answer:
37,500 7=thousands 4,800.87 7=hundredths
Step-by-step explanation:
From the given density function we find the distribution function,

(a)



(b)



(c)



Answer:
The intermediate step are;
1) Separate the constants from the terms in x² and x
2) Divide the equation by the coefficient of x²
3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression
Step-by-step explanation:
The function given in the question is 6·x² + 48·x + 207 = 15
The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;
6·x² + 48·x + 207 = 15
We get
1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192
6·x² + 48·x = -192
2) Dividing by 6 x² + 8·x = -32
3) Add the constant that completes the square to both sides
x² + 8·x + 16 = -32 +16 = -16
x² + 8·x + 16 = -16
4) Factorize (x + 4)² = -16
5) Compare (x + 4)² = -16 which is in the form (x + a)² = b
Given that original lenght of the board before cut
meter
Lenght of the board that is left after cutting from the original piece by Hernan
meter
Now we have to find the lenght of the piece which is cut.
To find that we just need to subtract smaller piece from larger piece
Required Length
meter
Required Length
meter
Required Length
meter
reduce the fraction
Required Length
meter
Hence final answer is
meter.