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3 years ago

10

The 2nd one is right just did the test

1 answer:

Vikki [24]3 years ago

4 0

Answer:

ok lol

Step-by-step explanation:

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Pete has 3 dollars less than what Linda has. If together has 81 dollars how much does each person have?

Makovka662 [10]

Answer:

Pete: 39, Linda: 42

Step-by-step explanation:

Suppose Pete has x dollars. If he has 3 dollars less than Linda, then Linda has 3+x dollars. Together, they have 81 dollars:

x+3+x=81

2x+3=81

2x=78

x=39

Since Pete has x dollars, and x=39, he has $39.

Linda has 3+x, which is 39+3 = $42

<em>I hope this helps! :)</em>

8 0

3 years ago

A hungry elf ate 35 of your muffins. That was 710 of all of them! With how many did you start?

KengaRu [80]

Answer:

2094.5 muffins

Step-by-step explanation:

The problem is a little bit messy, but i’m guessing you meant that the elf ate 35% of the muffins, which 35% is 710 muffins. so since 35% of muffins is 710 muffins, let’s multiply that by 2 so we can get 70%.

so 710 x 2 is 1420. so 70% of the muffins is 1420 muffins! sadly that’s not all of the muffins. we’re still missing another 30%. since we don’t know how many muffins are in 30%, let’s just take 710 muffins - 5%. when you do that you get 674.5. so now that we know how much is in 30%, let’s take 1420 + 674.5. when you do that you get 2094.5! so you started off with 2094 and a half muffins!

6 0

3 years ago

Question 2..plz help meee

Art [367]

refer to the attachment

7 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

4 years ago

Given that f(x) = x2 – 13x + 36 and g(x) = x – 9, find (f + g)(x) and express the result in standard form.

olga nikolaevna [1]

Answer:

x² - 12x + 27

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 13x + 36 + x - 9 ← collect like terms

= x² - 12x + 27 ← in standard form

5 0

3 years ago