Question

All my information is "solve"...no other instructions were given...

Answer 1

I assume we are solving for x see attachment.

Answer 2

Alrighty

add 6 to both sides and minus x² from both sides
√(3x)=6-x²
square both sides
3x=x⁴-12x²+36
minus 2x both sides
0=x⁴-12x²+3x+36
group and factor
how you do that
magic (I used my calculator)
we get
0=(x-3)(x-1.90057)(x²+4.90057x+6.13189)

set equal to 0
0=x-3
3=x

0=x-1.90057
1.90057=x

and the other one doesn't intersect have a 0

so the solutions are x=3 and x=1.90057


hold a second
if we test x=1.90057, we get a true statemtnt

but if we test x=3, we get 12=0 which is false



the only solution is x=1.90057