All categories

3 years ago

All my information is "solve"...no other instructions were given...

Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

I assume we are solving for x see attachment.

never [62]3 years ago

4 0

Alrighty

add 6 to both sides and minus x² from both sides
√(3x)=6-x²
square both sides
3x=x⁴-12x²+36
minus 2x both sides
0=x⁴-12x²+3x+36
group and factor
how you do that
magic (I used my calculator)
we get
0=(x-3)(x-1.90057)(x²+4.90057x+6.13189)

set equal to 0
0=x-3
3=x

0=x-1.90057
1.90057=x

and the other one doesn't intersect have a 0

so the solutions are x=3 and x=1.90057

hold a second
if we test x=1.90057, we get a true statemtnt

but if we test x=3, we get 12=0 which is false

the only solution is x=1.90057

You might be interested in

A study is conducted to test the hypothesis that people with glaucoma have higher than average blood pressure. The study include

natali 33 [55]

Answer: The confidence interval would be (120.6, 159.4).

Step-by-step explanation:

Since we have given that

n = 200

mean = $\bar{x}=140\ mm$

Standard deviation = $\sigma=25\ mm$

At 95% confidence interval, z = 1.96

So, 95% confidence interval would be

$\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=140\pm 1.96\times \dfrac{140}{\sqrt{200}}\\\\=140\pm 19.40\\\\=(140-19.4,140+19.4)\\\\=(120.6,159.4)$

Hence, the confidence interval would be (120.6, 159.4).

4 0

4 years ago

The final exam grade distribution for all students in the introductory statistics class at a local community college is displaye

PolarNik [594]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which set of anges can form a triangle

MArishka [77]

So, any set of three angles that add up to 180 degrees can form a triangle

6 0

3 years ago

Read 2 more answers

MARKING BRAINLEST IF CORRECT Solve for x. 66 6 7 110

kodGreya [7K]

Answer:

x =6

Step-by-step explanation:

17x + 8 + 66 + 74 +110 = 360

17x + 258 =360

17x = 360 -258

17x =102

x =6

8 0

3 years ago

All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A

Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

$P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%$

From which we deduce that

$P(A^c|B) = 10%, P(B^c) = 95%$

a) We are asked for the probability $P(A^c\cap B)$ . REcall the conditional probability formula that, given two events C,D the conditional probability $P(C|D) = \frac{P(C\cap D)}{P(D)}$ . Then we have that

$P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%$ .

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by $P(C) = P(C|A)P(A)+P(C|B)P(B)$ . Then

$P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%$

c) We are asked for the probability P(B^c|A^c). Recall that $P(A|B) = \frac{P(B|A)P(A)}{P(B)}$ . Then

$P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%$

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability $P(A\cup B)$ . We use the following

$P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%$

4 0

4 years ago