What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3
1 answer:
Answer:
<h2>
12q</h2>
Step-by-step explanation:
Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;
dy/dx = naxⁿ⁻¹
Rewriting the given equation as P = 6q² + 3q⁰
Using the formula to find the derivative;
dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹
dP/dq = 12q¹ + 0
dP/dq = 12q
<em>Hence the derivative of the function P with respect to q is 12q</em>
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