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baherus [9]
3 years ago
7

What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

<h2>12q</h2>

Step-by-step explanation:

Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;

dy/dx = naxⁿ⁻¹

Rewriting the given equation as P =  6q² + 3q⁰

Using the formula to find the derivative;

dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹

dP/dq = 12q¹ + 0

dP/dq = 12q

<em>Hence the derivative of the function P with respect to q is 12q</em>

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Solve for x(need help)
bija089 [108]

Answer:

x = 18

Step-by-step explanation:

I the given triangle, it appears that M and N are the midpoints of the segments BG and BD respectively. If it so, then let us solve it.

By mid segment theorem:

2MN = GD

2(6x - 51) = 114

12x - 102 = 114

12x = 114 + 102

12x = 216

x = 216/12

x = 18

4 0
3 years ago
Solve for angle B in right triangle ABC. <br><br> I got 53, is it right?
lara31 [8.8K]
Yup its 53 Degrees you got it right :)

8 0
3 years ago
Please help, I need input on if I did this correctly and you just substitute.
kow [346]

The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

Now multiply the common terms into inside the bracket.

           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

       $=\frac{641}{64}

       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

8 0
3 years ago
The coordinates of three vertices of square ABCD are A(−212,112),B(−212,−3), and C(2,112).
Lady_Fox [76]

Answer:

<em>P=760</em>

Step-by-step explanation:

Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.

Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).

This shape has sides that are parallel to both axes.

To calculate the perimeter we find the length of two sides.

The distance from A to B is the difference between their y-axis:

w=112-(-3)=115

The distance from A to C is the difference between their x-axis:

l=2-(-212)=215

It's evident this is not a square but a rectangle. The perimeter is

P=2w+2l=330+430

P=760

7 0
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A machine that produces a major part for an airplane engine is monitored closely. In the past, 12% of the parts produced would b
melamori03 [73]

Answer:

Wanna have sex?

Step-by-step explanation:

7 0
2 years ago
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