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baherus [9]
2 years ago
7

What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3

Mathematics
1 answer:
Ahat [919]2 years ago
4 0

Answer:

<h2>12q</h2>

Step-by-step explanation:

Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;

dy/dx = naxⁿ⁻¹

Rewriting the given equation as P =  6q² + 3q⁰

Using the formula to find the derivative;

dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹

dP/dq = 12q¹ + 0

dP/dq = 12q

<em>Hence the derivative of the function P with respect to q is 12q</em>

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Eighteen is 25% less than what number?
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72

Step-by-step explanation:

multiply 18 by 4,

since 100/4 is 25, and four quarters makes a dollar, multiply it by 4

18(4) = 72

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EXPAND AND SIMPLIFY<br>​
Anit [1.1K]

Answer:

5⁴a²

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(5³a³)÷5a-¹×5-²a²

5³a³÷5a-¹×5-²a²

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2 years ago
Estimate √97.5 / 1.96
evablogger [386]

Answer: 5


Step-by-step explanation:

 1. You have the following expression given in the problem above:

\frac{\sqrt{97.5}}{1.96}

2. You can estimate the result by rounding the numerator and the denominator.

3. As you can see, you can round up 97.5 to 100.

4. Then, you can round up 1.96 to 2.

5. Therefore, you have:

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3 0
2 years ago
CAN SOMEONE HELP ME WITH THIS?!
lutik1710 [3]

Answer:

a = 14

b = 24

c = 24.9

A = 33.2 degrees

B = 70 degrees

C = 76.8 degrees

Step-by-step explanation:

a/sin(A) = b/sin(B) = c/sin(C)

14/sin(A) = 24/sin(70)

sin(A)×24 = sin(70)×14

sin(A) = sin(70)× 14/24 = sin(70) × 7/12 = 0.548154029...

A = asin(0.548154029...) = 33.240464... degrees

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c = 24×sin(76.75954...)/sin(70) = 24.86133969...

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2 years ago
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