What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3

1 answer:

Ahat [919]2 years ago

4 0

Answer:

Step-by-step explanation:

Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;

dy/dx = naxⁿ⁻¹

Rewriting the given equation as P = 6q² + 3q⁰

Using the formula to find the derivative;

dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹

dP/dq = 12q¹ + 0

dP/dq = 12q

Hence the derivative of the function P with respect to q is 12q

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