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baherus [9]
3 years ago
7

What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

<h2>12q</h2>

Step-by-step explanation:

Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;

dy/dx = naxⁿ⁻¹

Rewriting the given equation as P =  6q² + 3q⁰

Using the formula to find the derivative;

dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹

dP/dq = 12q¹ + 0

dP/dq = 12q

<em>Hence the derivative of the function P with respect to q is 12q</em>

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Answer:

(2,16)

Step-by-step explanation:

y=-x+18

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Step-by-step explanation:

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2 inches

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3 years ago
Is the following expression true or false? Show your work.
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So now we have an equation

(x + 4)^2 • (x - 4)^2 -  (x^2 - 16)^2  = 0

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3 years ago
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