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baherus [9]
3 years ago
7

What is the first derivative of p with respect to q (i.e., differentiate P with respect to q)?P = 6q2 + 3

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

<h2>12q</h2>

Step-by-step explanation:

Given P = 6q² + 3, we are to find the derivative of the function with respect to q. Generally if y = axⁿ;

dy/dx = naxⁿ⁻¹

Rewriting the given equation as P =  6q² + 3q⁰

Using the formula to find the derivative;

dP/dq = 2(6)q²⁻¹ + 0(3)q⁰⁻¹

dP/dq = 12q¹ + 0

dP/dq = 12q

<em>Hence the derivative of the function P with respect to q is 12q</em>

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Explanation:

<h3>8.</h3>

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

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and

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<h3>9.</h3>

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

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