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USPshnik [31]
3 years ago
13

How to put 1.3, 1 1/3, 1.34 in order from least to greatest

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
7 0
11/3, 1.3, 1.34 Is the correct way to put it. PLZ give me the Brainliest answer. :)
77julia77 [94]3 years ago
5 0
The answer is, 1.3, 1 1/3, 1.34.
1.3 = 1.30
1 1/3= 1 x 3 =3 + 1 = 4/3= 4 divided by 3= 1.33
1.34=1.34
So, it'd be 1.30 , 1 1/3 , 1.34.
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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
3 years ago
T = AB-5 for A what would be the answer for A
Ainat [17]

The given equation solved for A is A = (T + 5)/ B

<h3>Solving linear equation</h3>

From the question, we are to solve the given equation for A

To solve the equation for A, we will simply make A the subject of the equation

The given equation is

T = AB - 5

Solving for A

T = AB - 5

Add 5 to both sides of the equation

T + 5 = AB - 5 + 5

T + 5 = AB

Divide both sides of the equation by B

That is,

(T + 5)/B = AB/B

(T + 5)/B = A

∴ A = (T + 5)/ B

Hence, the given equation solved for A is A = (T + 5)/ B

Learn more on Solving linear equation here: brainly.com/question/1531728

#SPJ1

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