Answer:
<h2>(3, -2)</h2>
Step-by-step explanation:
Put the coordinates of the points to the inequality and check:
y < -1/2x + 2
for (2, 3) → x = 2, y = 3
3 < -1/2(2) + 2
3 < -1 + 2
3 < 1 FALSE
============================
for (2, 1) → x = 2, y = 1
1 < -1/2(2) + 2
1 < -1 + 2
1 < 1 FALSE
============================
for (3, -2) → x = 3, y = -2
-2 < -1/2(3) + 2
-2 < -1.5 + 2
-2 < 0.5 TRUE
============================
for (-1, 3) → x = -1, y = 3
3 < -1/2(-1) + 2
3 < 1/2 + 2
3 < 2 1/2 FALSE
A function is a relation<span> (so, it is the set of ordered pairs) that does not contain two. The </span>domain is<span> the set </span>X= {1,2,3<span>,4} and the range is the subset {a,b,c} of </span>Y<span>.</span>
A) 9/24
Step One: Simplify all of the fractions
9/24 = 3/8
15/20 = 3/4
3/16 = 3/16
1/5 = 1/5
Step Two: Fine the answer that simplifies to 3/8
Answer:
1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.
2. Second Option is correct , because by reflecting the shape I across X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.
3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.
4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.
5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option
