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Firdavs [7]
3 years ago
6

Which is greater 6/11 or 5/9 or are they equal?

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

5/9

Step-by-step explanation:

6/11 is 0.54545454545

5/9 is 0.5555555556

Veronika [31]3 years ago
4 0

Answer:

6/11 < 5/9

So 6/11 is less then 5/9

Step-by-step explanation:

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Find the mode of the data set below.
kramer
The mode is 88. The mode is a number that is most repeated in a pattern, and here it is 88.

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4 0
3 years ago
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An equilateral triangle has a perimeter of 12 x + 18 units. Which expression can be used to show the length of one side of the t
adelina 88 [10]

Answer:

So each side length is 4s+6

Step-by-step explanation:

Since we know the triangle is an equilateral triangle, we know the perimeter of the triangle is given by since all the sides are the same length

P = 3s  where s is the side length

12x+18 = 3s

Divide each side by 3

12x/3 + 18/3 = 3s/3

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So each side length is 4s+6

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3 years ago
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The area of the square adjacent to two sides of a right triangle are 29.25 square units and 13 units 30 POINTS
Otrada [13]

Answer:

x=6.5\ units

Step-by-step explanation:

step 1

Find the length side of the smaller square

The area of the square is equal to

A=a^{2}

so

a^{2}=13

a=\sqrt{13}\ units

step 2

Find the length side of the larger square

The area of the square is equal to

A=b^{2}

so

b^{2}=29.25

b=\sqrt{29.25}\ units

step 3

Find the value of x

Applying the Pythagoras Theorem

x^{2} =a^{2}+b^{2}

substitute the values

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x^{2} =42.25

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6 0
3 years ago
"eight times the difference of a number and three is sixty-four"?
morpeh [17]

Answer:

the number would be 11

Step-by-step explanation:

8    ·    x - 3       =      64

________                 _          (divide both sides by 8)

8                                 8

x - 3  =   8

+ 3         + 3

x  = 11

(check:

11 - 3 = 8

8 x 8 = 64 )

5 0
2 years ago
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Use the distance formula to find the distance, to the nearest tenth, from S(7, −1) to V(−1, 3).
34kurt

Answer:  8.9 units (choice C)

Explanation:

We plug (x_1,y_1) = (7,-1) \text{ and } (x_2,y_2) = (-1,3)\\\\ into the distance formula to get the following

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(7-(-1))^2 + (-1-3)^2}\\\\d = \sqrt{(7+1)^2 + (-1-3)^2}\\\\d = \sqrt{(8)^2 + (-4)^2}\\\\d = \sqrt{64 + 16}\\\\d = \sqrt{80}\\\\d \approx 8.94427\\\\d \approx 8.9\\\\

4 0
2 years ago
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