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Firdavs [7]
3 years ago
6

Which is greater 6/11 or 5/9 or are they equal?

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

5/9

Step-by-step explanation:

6/11 is 0.54545454545

5/9 is 0.5555555556

Veronika [31]3 years ago
4 0

Answer:

6/11 < 5/9

So 6/11 is less then 5/9

Step-by-step explanation:

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Question 10 (1 point)
Diano4ka-milaya [45]

Answer:

borh are correct in the same order that you wrote them. fist you eliminate 1 from the orinal side to the other so the next step is also right you subtrac 8 mines 1 so equal to 7 ...

6 0
3 years ago
f(x) = 0.2^x is transformed 9 units right, compressed vertically by a factor of 1/6 and reflected across the x-axis. Write the t
postnew [5]

Answer:

The function g(x) is defined as g(x)=-\frac{1}{6}(0.2)^{x-9}.

Step-by-step explanation:

The given function is

f(x)=-(0.2)^x

The function f(x) transformed 9 units right, compressed vertically by factor of 1/6 and reflected across the x-axis.

The transformation of function is defined as

g(x)=kf(x+b)+c

Where, k is vertical stretch, b is horizontal shift and c is vertical shift.

If b>0, then the graph of f(x) shifts b units left and if b>0, then the graph of f(x) shifts b units right.

If c>0, then the graph of f(x) shifts c units upward and if c>0, then the graph of f(x) shifts c units downward.

The value of b is -9 because the graph shifts 9 units right. The value of k is 1/6. If the graph of function f(x)reflect across x-axis, therefore the function is defined as -f(x).

g(x)=\frac{1}{6}(-f(x-9))

g(x)=-\frac{1}{6}(0.2)^{x-9}            [\because f(x)=-(0.2)^x]

Therefore the function g(x) is defined as g(x)=-\frac{1}{6}(0.2)^{x-9}.

7 0
3 years ago
Read 2 more answers
I might have to kiss you if you answer this
SVEN [57.7K]
Hey can i get a kiss
4 0
3 years ago
Read 2 more answers
(ignore thisssssssssssss)
den301095 [7]

Answer:

ok

Step-by-step explanation:

8 0
3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
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