This is a geometric sequence because each term is a constant multiple, called the common ratio, of the previous term. In this case the common ratio, noted as "r", is:
8/-2=-32/8=128/-32=r=-4
The first term is -2
Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.
Since we know r and a for this problem already we can say:
a(n)=-2(-4)^(n-1)
Answer:
hard question you got there
Step-by-step explanation:
Answer:
a. 13/3
b. 3 3/4
d. 1 7/8
c. 7/2
Step-by-step explanation:
a. 4 1/3 given
4*3=12 multiply the whole numbers with the denominator
12+1 =13 add the numerator to the product
13/3 put sum over denominator
b. 15/4 given
15/4=3 with a remainder of 3 divide numerator by denominator
3 3/4 rewrite as mixed number
d. 15/8 given
15/8=1 with a remainder of 7 divide numerator by denominator
1 7/8 rewrite as mixed number
c. 3 1/2 given
3*2=6 multiply whole number by denominator
6+1=7 add numerator to product
7/2 put sum over denominator
