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3 years ago

Select the equivalent expression. (x^-3*y^3)^-7=? Choose 1 answer:

Mathematics

1 answer:

Zina [86]3 years ago

8 0

Answer:

The equivalent expression for this equation is x²¹ × y⁻²¹

Step-by-step explanation:

When you are multiplying exponents that are in parentheses, you multiply the exponential numbers together. So, for this problem, we will multiply the exponents together so we can get our final equivalent expression.

(x⁻³ × y³)⁻⁷

So, we will multiply -3 by -7 and we will also multiply 3 by -7 because those are our exponential numbers.

x²¹ × y⁻²¹

So, this is the final expression that is equivalent to our equation.

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Water decomposes to produce hydrogen gas and oxygen gas. How many grams of water would be required to produce 10.0 moles of hydr

lesya692 [45]

Answer:

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3 years ago

An automobile manufacturer claims that its van has a 40.3 miles/gallon (MPG) rating. An independent testing firm has been contra

vovikov84 [41]

Answer:

The value of the test statistic is -2.64.

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected(claimed) mean, $\sigma$ is the standard deviation and n is the size of the sample.

An automobile manufacturer claims that its van has a 40.3 miles/gallon (MPG) rating.

This means that $\mu = 40.3$

After testing 250 vans, they found a mean MPG of 39.9. Assume the standard deviation is known to be 2.4.

This means, respectively, that:

$n = 250, X = 39.9, \sigma = 2.4$

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{39.9 - 40.3}{\frac{2.4}{\sqrt{250}}}$

$t = -2.64$

The value of the test statistic is -2.64.

7 0

3 years ago

What are the solutions of the equation x² = 49

olga55 [171]

To find x you do √49=x

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3 years ago

in a pottery class, a teacher has 2/3 pound of clay for 6 students. If she gives each student a equal amount of clay, how much w

Jlenok [28]

She will give 1/9 pound of clay to each student

8 0

3 years ago

Read 2 more answers

How do I do this? *Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

7 0

2 years ago