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Amanda [17]
3 years ago
13

Simplify the expressions if it is possible. if the expression is already simplified write the word simplified.

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0
1. -5x+3x = 6
-2x /-2=6/-2
x = -3

3.9p+18 -4p+13
=5p =-31
p = -31/5
= -6.2
5.45n+16m-12+5n -2m
50n + 14 m = 12
2(25n+7m) /2 = 12/2
25n+ 7m = 6
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Answer:

Greatest to Least:

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A.) 5<br> B.) 6<br> C.) 7<br> D.) 8
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Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of t
jenyasd209 [6]

Answer:

97.92% probability that the mean score of your sample is between 22 and 28

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 25, \sigma = 6.5, n = 25, s = \frac{6.5}{\sqrt{25}} = 1.3

What is the probability that the mean score of your sample is between 22 and 28

This is the pvalue of Z when X = 28 subtracted by the pvalue of Z when X = 22. So

X = 28

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{28 - 25}{1.3}

Z = 2.31

Z = 2.31 has a pvalue of 0.9896

X = 22

Z = \frac{X - \mu}{s}

Z = \frac{22 - 25}{1.3}

Z = -2.31

Z = -2.31 has a pvalue of 0.0104

0.9896 - 0.0104 = 0.9792

97.92% probability that the mean score of your sample is between 22 and 28

8 0
3 years ago
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