Answer:
Theoretical probability: 50/100 or 50%
Experimental probability: 12/20 or 60%
Step-by-step explanation:
Let's find out both probabilities asked.
Theoretical probability:
In the whole bank, here are 100 coins (20 nickels + 30 quarters + 50 one-dollars), among which there are 50 one-dollar coins. So the probability to pick up a one-dollar coin is 50 out 100, so...
TP = 50/100 or 50%
Experimental probability:
For the experimental probability, we know Jonathan picked out 20 coins, out of which 12 were one-dollar coins, so the probability is 12 out of 20...
EP = 12 / 20 = 60%
Answer:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
Step-by-step explanation:
Solve for u:
(x sin(A) - u cos(A))^2 + (x cos(A) + y sin(A))^2 = x^2 + y^2
Subtract (x cos(A) + y sin(A))^2 from both sides:
(x sin(A) - u cos(A))^2 = x^2 + y^2 - (x cos(A) + y sin(A))^2
Take the square root of both sides:
x sin(A) - u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
-u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) - x sin(A) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or -u cos(A) = -x sin(A) - sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
Answer: u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
The answer to this question is:
y = 4x - 13
Answer:
32
Step-by-step explanation:
Adding 12 to 20 will give you the answer. To further describe it, if we make x the unknown number, the equation is:
x-12=20
then you can isolate x to get the unknown number
x=20+12=32
Answer:
2 bears in 2020.
Step-by-step explanation:
We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
We will use exponential decay formula to solve our given problem as:
, where,
y = Final quantity,
a = Initial value,
r = Decay rate in decimal form,
x = Time
Upon substituting our given values in above formula, we will get:
, where x corresponds to year 2000.
To find the population in 2020, we will substitute 
in our equation as:
Therefore, 2 bears are there predicted to be in 2020.
Since population is decreasing so population is best described as exponential decay.
