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alexgriva [62]
2 years ago
10

Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab

le feature to confirm that the coordinates of both points satisfy your equation.) (-5, 10) and (5, -10) a. y = 2x-10 b. C. d. y = 2x y = -2x+ 20 y=-2x A​
Mathematics
1 answer:
siniylev [52]2 years ago
6 0

Answer:

y = -2x

Step-by-step explanation:

It passes through -5, 10 and 5, -10

gradient = Δy/Δx

gradient = -10 - 10 / 5 -- 5

gradient = -20 / 10

gradient = -2

let's use -5, 10 for y = mx + b

10 = -2(-5) + b

10 = 10 + b

b = 10 - 10

b = 0.

the equation of the line is just y = -2x

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The radius of a circle is 2.6 in. Find the circumference <br> to the nearest tenth.
Georgia [21]

Answer:

16.

Step-by-step explanation:

since given the radius and the formula of the circumference of a circle is 2pie*r

5 0
3 years ago
If x=9 and y=−3, evaluate the following expression:7(2x−3y)​
LuckyWell [14K]

Answer:

189

Step-by-step explanation:

You can replace the values of x with 9 and the values of y with (-3).

7(2x-3y) = 7(2 × 9 - 3 × -3)

             = 7(18 - -9)

             = 7(18+9)

             = 7 × 27

             = 189

7 0
3 years ago
Read 2 more answers
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
3 years ago
Help me with this question please
stich3 [128]

Answer:

(-1,9)

Step-by-step explanation:

union contains both sets.

4 0
3 years ago
A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend
anyanavicka [17]

Answer:

The equation of Grant's path is y = 4 - x over 2 ⇒ 2nd answer

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0)

The formula of the slope of a line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ Grant's path is a line from point A to point B

∴ The equation of AB represents Grant's path

Lets find the slope of AB using the formula of the slope above

∵ A = (8 , 0)

∵ B = (-4 , 6)

∴ x_{1} = 8 and x_{2} = -4

∴ y_{1} = 0 and y_{2} = 6

∵ m=\frac{6-0}{-4-8}=\frac{6}{-12}

∴ m=-\frac{1}{2}

Substitute the value of m in the form of the equation

∵ y = m x  + b

∴ y = -\frac{1}{2} x + b

∵ b is the value of y at x = 0

∵ y = 4 at x = 0 ⇒ from the figure

∴ b = 4

∴ y = -\frac{1}{2} x + 4

We can write -\frac{1}{2} x as -\frac{x}{2}

∴ y =  -\frac{x}{2} + 4

- Switch the two terms of the right hand side

∴ y = 4 -  \frac{x}{2}

The equation of Grant's path is y = 4 -  \frac{x}{2}

4 0
3 years ago
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