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jeka57 [31]
3 years ago
9

Assume that 6 people, including. the husband and wife pair, apply for 5 sales positions. People are hired at random. What is the

probability that one is hired and one is not?
Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
Probability that one is hired ans one not:
P ( A ) = (2 C 1 * 4 C 4) / 6 C 5 =
= ( 2 * 1 ) / 6 = 2/9 = 1 / 3
Answer: 1/3  or  33.33% 
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How many hours and minutes from noon to a quarter to four in the afternoon?
Alex_Xolod [135]
It would be 3:45 because 12:00 + 3:00= 3:00+0:45=3:45 and if u were to add another quarter (15mins) itd be 4:00
3 0
3 years ago
Which expression shows a sum of three terms.
vladimir1956 [14]

Answer:  B) 3+y+3

This can be simplified to y+6, but the current un-simplified expression has 3 terms.

======================================

Explanation:

Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.

Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.

Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.

Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.

5 0
3 years ago
Eddie ended round one of a game show with 800 points. In round two, he scored -400 points
german

Answer:

400

Step-by-step explanation:

800-400=400

8 0
3 years ago
Read 2 more answers
Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10
Brums [2.3K]

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

==>Interquartile range = Q3 - Q1 = 5-3 = 2

3 0
3 years ago
In a test of the effectiveness of garlic for lowering​ cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels
Nata [24]

Answer:

There is enough evidence to support the claim

Step-by-step explanation:

We are conduction a hypothesis test for dependent samples.  We want to see if there was a change in the test subjects cholesterol levels.  

For our situation:

n = 64

d = 0.7

s = 1.72

µ(d) = 0

The hypothesis are:

H0:  µ(d) = 0

Ha:  µ(d) > 0

This is a right tailed test.  

We are testing at the 1% level of significance.  Our critical region is z > 2.325

If our test statistic is in this region, we will reject the null hypothesis

See attached photo for the calculation of the test statistic and conclusion of the test

7 0
2 years ago
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