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3 years ago

What is the product? (4y - 3) (2y^2 +3y - 5)

Mathematics

1 answer:

igomit [66]3 years ago

8 0

(4y-3)(2y²+3y-5)

First , let's start with "4y"

4y*2y² = 8y³

4y*3y = 12y²

4y*-5 = -20y

Next, let's multiply by "-3"

-3*2y² = -6y²

-3*3y = -9y

-3*-5 = 15

Now, let's combine all of our values.

8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15

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3 years ago

Which expressions are equivalent to Negative 9 (two-thirds x + 1)? Check all that apply.

Sav [38]

Answer:

$-9(\frac{2}{3}x) + 9(1)\\ \\-6x + 9$

Explanation:

Before we begin, remember the following rules:

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$a(b+c) = ab+ac$

2- Simplification of fractions:

$\frac{xy}{yz}=\frac{x}{z}$

3- Signs in multiplication:

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Now, for the given problem, we have:

$9 (\frac{2}{3}x + 1)$

Starting with the distributive property:

$-9 (\frac{2}{3}x +1) = -9(\frac{2}{3}x) - (-9)(1) = -9(\frac{2}{3}x) + 9(1)$

..................>This corresponds to option 1

Now, we simplify the output from the above step:

$-9(\frac{2}{3}x) + 9 = \frac{-9*2}{3}x + 9 = -6x+9$

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3 years ago

Read 2 more answers

Could someone pls help me and explain this if you know it!!

yanalaym [24]

Answer:

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3 years ago