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bazaltina [42]
3 years ago
11

What is 2/5 closer to

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

Depends on what it is

Step-by-step explanation:

I can't tell you because I don't know what we are comparing. :)

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Can you plz find the area of the parallelogram??
levacccp [35]
13.5·18=243
Base* Hight= Answer 

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Can 0.1/100 be simplified?
FrozenT [24]
No 0.1/100 cannot be simplified
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Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random
Maurinko [17]

Answer:

D)

(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the random sample size 'n' = 50

The sample proportion

                       p^{-} = \frac{32}{50} = 0.64

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n},  } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Level of significance = 0.90

Z₀.₉₀ = 1.645

(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })

(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

<u><em>Final answer:-</em></u>

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0
3 years ago
Help I am stuck on this question
Aleksandr-060686 [28]
A = b * h 

   = 18.5 * 18

   = 333 m^2

Good luck :)
4 0
3 years ago
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Jan and Laura have a total of 3 same sized cookies they want to divide equally between the two of them. What fraction of the coo
xenn [34]
They should get 1.5 (1 1/2) cookies because 3÷2= 1.5
3 0
3 years ago
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