13.5·18=243
Base* Hight= Answer
No 0.1/100 cannot be simplified
Answer:
D)

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month
(0.52846 , 0.75166)
Step-by-step explanation:
<u><em>Step:-1</em></u>
Given that the random sample size 'n' = 50
The sample proportion

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

<u><em>Step(ii):-</em></u>
Level of significance = 0.90
Z₀.₉₀ = 1.645


(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)
(0.52846 , 0.75166)
<u><em>Final answer:-</em></u>
90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month
(0.52846 , 0.75166)
A = b * h
= 18.5 * 18
= 333 m^2
Good luck :)
They should get 1.5 (1 1/2) cookies because 3÷2= 1.5