What is the product of (-1/4) times (-3/7)

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago

6m-2 = m+13 how do i solve it

kakasveta [241]

First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3

4 0

3 years ago

Two cities are 45 miles apart. Two trains, with speeds of 70 mph and 60 mph, leave the two cities at the same time so that one i

KATRIN_1 [288]

The distance between the trains is changing at the rate of (70 -60) = 10 mph. They will be in the same place (45 mi)/(10 mi/h) = 4.5 hours after they leave their respective cities. They will be 10 miles apart both 1 hour before that time and one hour after that time.

The trains will be 10 miles apart 3.5 hours after leaving.

They will be 10 miles apart the second time 5.5 hours after leaving.

4 0

3 years ago

Read 2 more answers

Tom has already baked 4 cakes, and he can bake 1 cake with each additional stick of butter he buys. How many additional sticks o

Serjik [45]

Answer:

since it takes 1 additional stick to bake a cake,then it takes 84 additional sticks to bake 42 cakes

3 0

3 years ago

Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.

klasskru [66]

Answer:

See the explanation

Step-by-step explanation:

We know that

f(x) = 2x⁶ + 3x⁴ - 4x³ + (1/x) - sin2x

Lets calculate the derivatives:

f'(x) = 6(2x⁵) + 4(3x³) - 3(4x²) -( 1/x²) - 2(cos2x)

f'(x) = 12x⁵ + 12x³ - 12x² - (1/x²) - 2cos2x

Similarly:

f''(x) = 60x⁴ + 36x² - 24x + (2/x³) + 4sin2x

f'''(x) = 240x³ + 72x - 24 - (6/x⁴) + 8cos2x

Rearrange:

f'''(x) - 240x³ +72x - (6/x⁴) + 8cos2x - 24

f''''(x) = 720x² + 72 + (24/x⁵) - 16sin2x

Rearrange:

f''''(x) = 720x² + (24/x⁵) - 16sin2x +72

8 0

3 years ago