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ivolga24 [154]
3 years ago
14

There are 12 girls and 18 boys in a class what is the largest number of groups they can be split into and have the same number o

f boys and girls on each team
Mathematics
1 answer:
leonid [27]3 years ago
8 0
6 bc there would be 2 girls and 3 boys on each team
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Steven earns extra money babysitting. He charges $37.50 for 6 hours and $50.00 for 8 hours.
PilotLPTM [1.2K]
We have that
x------------------> <span>represent the number of hours Steven babysits
y----------------- > </span><span>represent the amount he charges

for x=6 hours
y=</span><span>$37.50 ----------------> y/x=37.5/6=6.25
</span>for x=8 hours
y=$50---------------------> y/x=50/8=6.25

therefore
y=6.25x

the answer is 
y=6.25x

8 0
3 years ago
The Russian soccer goalie has saved 17 out of the last 20 shots but the Italian soccer goalie has saved 12 out of the last 14 sh
Novosadov [1.4K]

Answer:

The italian goalie: 85.7%

Step-by-step explanation:

17 / 20 = 85% (Russian)

12 / 14 = 85.7% (Italian)

4 0
2 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
3 years ago
Can anyone help me with this its really urgent!!
Nesterboy [21]

Answer:

h = 2 cm

402 over 3.14 x (8) to the power of two. SImplifies to about the answer of 2

7 0
2 years ago
Plz help with this problem I need to find the length of CB???
dezoksy [38]
CB is equal to 10m  you can tell this bye the side DC being 20 m and the angle of DC is half of CB so that means that CB has to be 10 m
4 0
3 years ago
Read 2 more answers
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