False the Pythagorean theorem is A2+B2=C2 hope this helps!
Answer:
A, C, D
Step-by-step explanation:
One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.
A(x) = ((x -2)x -4)x +3
A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)
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B(x) = ((x +3)x -2)x -6
B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor
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C(x) = (x -2)x^3 -27
C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)
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D(x) = (x^3 -20)x -21
D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)
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The polynomials of choice are A(x), C(x), and D(x).
Answer:
Step-by-step explanation:
<u>The rule for this dilation is:</u>
<u>Apply this rule to point B(4, 6):</u>
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
x=12
Step by step explanation: