All categories

3 years ago

Oh no!! not another one again worth 12 points picture is attached below

Mathematics

1 answer:

love history [14]3 years ago

6 0

Answer:

Step-by-step explanation:

plz mark me as brainliest

You might be interested in

Help asap i’ll give a brainliest

Oduvanchick [21]

Answer:

False

Step-by-step explanation:

There is not a linear pattern to the table

4 0

3 years ago

A. 11.1 B. 6.7 C. 13 D. 4.1

nexus9112 [7]

Answer:

Line AE & Line AD have the same in measurement.

3 0

3 years ago

The sum of 6 consecutive odd numbers is 204. What is the fourth number in this sequence?

Korolek [52]

204 /6 = 34

29 +31 +33 + 35 +37 +39 = 207

4th number = 35

6 0

3 years ago

Read 2 more answers

Solve for x. Each figure is a rhombus.

alisha [4.7K]

Answer:

you f yourelf

Step-by-step explanation:

hihhihihih

7 0

3 years ago

In a random sample of 60 dog owners enrolled in obedience training, it was determined that the mean amount of money spent per ow

Anton [14]

Answer: $(\$106.29,\ \$112.37)$

Step-by-step explanation:

Given : Sample size : $n=60$

The mean amount of money spent per owner = $\$109.33\text{ per class}$

Standard deviation : $\sigma=\$12$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

We know that the confidence interval for population mean is given by :-

$\mu\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$109.33\pm(1.96)\dfrac{12}{\sqrt{60}}\\\\\approx109.33\ \pm\ 3.04\\\\\approx(109.33-3.04,\ 109.33+3.04)\\\\(106.29,\ 112.37)$

Hence, the 95% confidence interval for the mean amount spent per owner for an obedience class will be $(\$106.29,\ \$112.37)$

6 0

3 years ago