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Vilka [71]
3 years ago
10

An artist painted a mural measuring 9’ x 20 1/2’ find the area and perimeter of the mural

Mathematics
1 answer:
Ann [662]3 years ago
7 0
The difference is 180 is the correct answer for the problems
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What system of inequalities is shown in the graph?
REY [17]
I think the answer is C
3 0
3 years ago
Ed stein paid $40.00 interes tonaloan
KIM [24]

Answer:

The rate of interest paid on the principal amount is 8%.

Step-by-step explanation:

Here, Principal Amount = $2,000

Time = 3 months = (3/ 12 ) Years = 0.25 years

Rate = R

Interest Amount  = $40

Now, as we know :

Simple Interest  = \frac{P \times R \times T}{100}

⇒40  = \frac{2,000 \times R \times 0.25}{100}\\\implies R = \frac{40 \times 100}{2000 \times 0.25}   =8

or, R = 8%

Hence, the rate of interest paid is 8%.

6 0
4 years ago
Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

8 0
3 years ago
Can someone please help its due soon.
docker41 [41]

Answer:

the 4th one is the answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In 6 years, Mariya will be as old as Vikram is now. In 2 years, Vikram will be three times older than Mariya. Find their ages no
Damm [24]

Answer:

Mariya is 1 year old

Vikram is 7 years old

Step-by-step explanation:

Here, we want to know the present ages of Mariya and Vikram.

Let the present age of Mariya be M and the present age of Vikram be V

From the question, we are told that in 6 years time, Mariya will be as old as Vikram is now

Thus, mathematically;

M + 6 = V ••••••(i)

Furthermore , in 2 years time Vikram will be 3 time older than Mariya

Mathematically;

( V + 2) = 3( M + 2)

V + 2 = 3M + 6

V = 3M + 6-2

V = 3M + 4 •••••••(ii)

So let’s equate the V

3m + 4 = m + 6

3m -m = 6-4

2m = 2

m = 1

But V = m + 6

V = 1 + 6

V = 7

3 0
3 years ago
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