An artist painted a mural measuring 9’ x 20 1/2’ find the area and perimeter of the mural

What system of inequalities is shown in the graph?

REY [17]

I think the answer is C

3 0

3 years ago

Ed stein paid $40.00 interes tonaloan

KIM [24]

Answer:

The rate of interest paid on the principal amount is 8%.

Step-by-step explanation:

Here, Principal Amount = $2,000

Time = 3 months = (3/ 12 ) Years = 0.25 years

Rate = R

Interest Amount = $40

Now, as we know :

Simple Interest = $\frac{P \times R \times T}{100}$

⇒ $40 = \frac{2,000 \times R \times 0.25}{100}\\\implies R = \frac{40 \times 100}{2000 \times 0.25} =8$

or, R = 8%

Hence, the rate of interest paid is 8%.

6 0

4 years ago

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Can someone please help its due soon.

docker41 [41]

Answer:

the 4th one is the answer

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

In 6 years, Mariya will be as old as Vikram is now. In 2 years, Vikram will be three times older than Mariya. Find their ages no

Damm [24]

Answer:

Mariya is 1 year old

Vikram is 7 years old

Step-by-step explanation:

Here, we want to know the present ages of Mariya and Vikram.

Let the present age of Mariya be M and the present age of Vikram be V

From the question, we are told that in 6 years time, Mariya will be as old as Vikram is now

Thus, mathematically;

M + 6 = V ••••••(i)

Furthermore , in 2 years time Vikram will be 3 time older than Mariya

Mathematically;

( V + 2) = 3( M + 2)

V + 2 = 3M + 6

V = 3M + 6-2

V = 3M + 4 •••••••(ii)

So let’s equate the V

3m + 4 = m + 6

3m -m = 6-4

2m = 2

m = 1

But V = m + 6

V = 1 + 6

V = 7

3 0

3 years ago