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balandron [24]
3 years ago
15

Explain how to find the constant rate of change from the verbal description below.

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

62miles/1hr

Step-by-step explanation:

In order to get the rate of change I divided 124 miles by 2 hours to get 62 miles.

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write the equation of the line perpendicular to y= 5/2x+2 that passes through the point (-7,9). Type an answer using slope-inter
lianna [129]

Answer:

y - (-7)  =  4/5(x - 9)

y + 7 = 4/5 ( x - 9)

Step-by-step explanation:

those are

the answers

7 0
2 years ago
Lisa spends 1/5 of an hour doing her math homework and 1/3 of an hour doing her social studies homework. What fraction of an hou
Sveta_85 [38]
To solve this, all you have to do is add 1/5 and 1/3.
Well, you might be thinking, "But the denominators are not the same! Fractions have to have like denominators in order to be added together!" And you are right. So, all we have to do, is make them both have the same denominator. To do this, we have to multiply both the numerator and denominator by the same number to find an equivalent fraction.
For 1/5, we can multiply both the numerator and denominator by 3, to get 3/15. 
Likewise, we can multiply both the numerator and denominator of 1/3 by 5, to get 5/15.
Now, you can easily add 3/15 and 5/15 because all you have to do is add the numerators, because the denominators are the same!
3/15+5/15=8/15, so she spends 8/15 hour on her math and social studies homework.
Hope I helped!
3 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
What is an equation for the line that passes through the coordinates (2, 0) and (0, 3)?
alexdok [17]
Answer:
Not sure if this is correct but I hope this helps :)

8 0
3 years ago
Need Help!
Nezavi [6.7K]

Answer:

fraction 1 and 3 over 5

Step-by-step explanation:

2:3 is equal to 8 blocks

5:12 is equal to 5 blocks

if you divide them, the result is:

8/5 which is the same as 1 3/5

because 5 is contained 1 time in 8 and the rest is 3

7 0
3 years ago
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