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Dmitry [639]
3 years ago
15

Mr. Green maintains a spreadsheet containing data on all of his employees, including name, job profile, monthly salary, and home

address. Which of the following options will best help him find information on all the employees working on the technology team?
A. sorting the data by the names of the employees
B. performing a custom filter based on job profile
C. sorting the data first by name and then by job profile
Computers and Technology
1 answer:
marta [7]3 years ago
6 0
The answer is C because he'll be able to search up the employees name then it will tell him all the information he needs along with their job profile
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Irina-Kira [14]

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6 0
3 years ago
company gives the following discount if you purchase a large amount of supply. Units Bought Discount 10 - 19 20% 20 - 49 30% 50
ratelena [41]

Answer:

In Python:

order = int(input("Order: "))

discount = 0

if(order >= 10 and order <20):

    discount = 0.20

elif(order >= 20 and order <50):

    discount = 0.30

elif(order >= 50 and order <100):

    discount = 0.35

elif(order >= 100):

    discount = 0.40

price = order * 4.1

discount = discount * price

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

Explanation:

This prompts the user for number of orders

order = int(input("Order: "))

This initializes the discount to 0

discount = 0

For orders between 10 and 19 (inclusive)

if(order >= 10 and order <20):

-----------discount is 20%

    discount = 0.20

For orders between 20 and 49 (inclusive)

elif(order >= 20 and order <50):

-----------discount is 30%

    discount = 0.30

For orders between 50 and 99 (inclusive)

elif(order >= 50 and order <100):

-----------discount is 35%

    discount = 0.35

For orders greater than 99

elif(order >= 100):

-----------discount is 40%

    discount = 0.40

This calculates the total price

price = order * 4.1

This calculates the pre discount

discount = discount * price

This prints the report

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

3 0
3 years ago
What is a common indicator of a phishing attempt cyber awareness 2022
vivado [14]

There are several types of malicious document. A common indicator of a phishing attempt cyber awareness 2022 is that It includes a threat of dire circumstances.

  • Phishing attacks often makes use of email or malicious websites to infect the machine with malware and viruses so as to collect personal and financial information.

Cybercriminals often uses different means to lure users to click on a link or open an attachment that infects their computers thereby producing vulnerabilities for criminals to use to attack.

Learn more from

brainly.com/question/24069038

7 0
2 years ago
What is intellectual property?
xz_007 [3.2K]

Answer:

The 3rd one

Explanation:

Intellectual property refers to creations of the mind: inventions; literary and artistic works; and symbols, names and images used in commerce. Intellectual property is divided into two categories: Industrial Property includes patents for inventions, trademarks, industrial designs and geographical indications.

7 0
3 years ago
Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument
timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0
3 years ago
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