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3 years ago

4. Carson said that when you divide two negative decimals the answer will be greater than 0.

1 answer:

3 0

(a) Carson's statement is always true.
For example: (-7.2)/(-2.4)= 3 >0
(-1.6)/(-0.8)= 2 >0

(b) When we divide two negative decimals, we divide the decimals and don't care about the sign, for the sign is always positive.

Hope this helps~

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Which of the following is the point and slope of the equation y + 5 = 3(x + 9)?

Tatiana [17]

Answer:

Option B, (-9, -5), 3

Step-by-step explanation:

<u>The point slope form in: y - y1 = m(x - x1)</u>

m is the slope

(x1, y1) is the point

<u>Step 1: Determine what the slope and point is their equation</u>

y + 5 = 3(x + 9)

3 is the slope

(-9, -5) is the point

Answer: Option B, (-9, -5), 3

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3 years ago

24kids will attend next week’s field trip. If 5 kids can fit each car. How many cars will be needed?

Kipish [7]

Answer:

The answer is 5.......

Step-by-step explanation:

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4 years ago

Read 2 more answers

use the elimination method to solve the system of equations choose the correct ordered pair 7x+4y=39 2y+4y=14

Anvisha [2.4K]

$x = 5 \: and \: y = 1.$

Step-by-step explanation:

$7x + 4y = 39 \: - {eq}^{n} (1)$

$2x + 4y = 14 \: \: - {eq}^{n} (2)$

Multiply Equation no (1) with 2 and Equation no (2) with 7.

$14 x + 8y = 78.$

$14x + 28y = 98.$

$( - ) \: \: \: ( - ) \: \: \: ( - )$

$0x + -20y = - 20$

$- 20y = - 20$

$y = \frac{ - 20}{ - 20}$

$y = 1$

Substitute the value of "y" in Equation no (1)

$7x + 4y = 39.$

$7x + 4(1) = 39.$

$7x + 4 = 39.$

$7x = 39 - 4$

$7x = 35.$

$x = \frac{35}{7}$

$x = 5.$

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3 years ago

Read 2 more answers

>>>>>>>>>(look at my other question)

aniked [119]

where is your other question? is this spam?

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3 years ago

Find two numbers, if their sum is −11 and their difference is 41

snow_tiger [21]

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

$a+b=s\\a-b=d$

Then adding the equations and dividing that sum by 2, you get

$(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}$

You can subtract the second eqution from the first and get a similar result for the smaller number

$(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}$

These are the formulas we used above.

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4 years ago