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3 years ago

Which is the distance from point A to B?

Mathematics

1 answer:

Aleks04 [339]3 years ago

5 0

Answer:

D) radical 26

Step-by-step explanation:

So this is a question where you need to find the hypotenuse of a triangle

the sides are 1 and 5

you can use Pythagoras (a^2+b^2=c^2)

substitute the values in

1^2+5^2=c^2

simplify the exponents

1+25=c^2

add them together

26=c^2

take the square root of 26

the answer is radical 26

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Need help asap!!!!!!

Mrac [35]

Answer: x=4

Step-by-step explanation: first you should write it out like it is telling you. put a line and EG is the line and f is in the middle of the two looks kinda like this E F G but they are on a line EG= 25 that means the whole thing equals 25. EF= 2x-6 and FG= 4x+7. when you plug that in it should look like this 25=2x-6+4x+7 then solve.

3 0

3 years ago

Which of the following are solution to the inequality below -4w - 2 < -38

FromTheMoon [43]

Answer:

w > 9

Step-by-step explanation:

Solve the inequality by using inverse operations.

-4w - 2 < -38

-4w < -36

w > 9

Like solving equations, inequalities should be solved using inverse operations. However, unlike equations, when you divide or multiply by a negative the sign changes.

8 0

3 years ago

Can someone help me ? And show me the steps

kow [346]

If the line is parallel, it has the same slope. So now just find the y intercept and put it into slope-intercept form

3 0

3 years ago

Solve for x: <br> 3x+2y=7

iVinArrow [24]

$3x+2y=7\ \ \ |subract\ 2y\ from\ both\ sides\\\\3x=7-2y\ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\dfrac{7-2y}{3}}$

8 0

3 years ago

A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s

yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

$x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2} = \frac{1 \pm 9 }{-0.4}$

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0

3 years ago