Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8
1 answer:
the equation of a line perpendicular to and passes through the point (-6,8) is
Step-by-step explanation:
We need to write equation of line perpendicular to and passes through the point (-6,8)
Since the line is in slope-inetercept form
the slope of line m = 0.25
As, the new line is perpendicular to the given line so, slopes of lines that are perpendicular are: slope = -1/slope1
So, slope will be -1/0.25 = -4
Now, finding y-intercept.
So, value of y-intercept b = 30
Now the equation of the required line having slope m= -4 and b =30 will be:
So, the equation of a line perpendicular to and passes through the point (-6,8) is
Keywords: Equation of line, slope-intercept form
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