The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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In a trapezoid, two opposite sides are parallel and are called bases.
In this trapezoid, the top and bottom sides are parallel and are the bases.
The right side that intersects both bases is a transversal.
When parallel lines are cut by a transversal, same-side interior angles are supplementary. The measures of supplementary angles add to 180 deg.
x + 72 = 180
x = 180 - 72
x = 108 deg
1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
Answer:
60
Step-by-step explanation:
Look at the attachment
Answer:
C. -21 is your answer
Step-by-step explanation:
Solve for t. Isolate the variable t in the first equation, then use the number gotten to solve the second equation.
3t - 7 = 5t
First, subtract 3t from both sides
3t (-3t) - 7 = 5t (-3t)
-7 = 5t - 3t
-7 = 2t
Isolate the variable (t). Divide 2 from both sides
(-7)/2 = (2t)/2
t = -7/2
t = -3.5
Plug in -3.5 for t in the second equation
6(t) =
6(-3.5) =
6(-3.5) = -21
C. -21 is your answer
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