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Gnesinka [82]
3 years ago
15

A handyman charges a fixed rate of R to visit a customers house. In addition, the hardy man charges an hourly rate for H for eac

h hour worked. Write a formula to represent T the total amount this handyman would charge for a job that requires N hours of work?
Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

T == R + NH

Step-by-step explanation:

The fixed rate R is added to the hourly charges to get the total T. The hourly charges are the product of the number of hours and the charge per hour, NH.

The sum is then ...

... T = R + NH

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Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

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80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
The U.S. Mint produces quarters that weigh about 5.67 grams each. After the
lesantik [10]
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\to \bold{|x-5.67|=0.02}\\\\

heaviest\bold{=5.69\ g\\\\}

lighest\bold{=5.65\ g\\\\}

Evaluating the each expression:  

\to \bold{q = -8}\\\\ \to \bold{r = -6}\\\\ \to \bold{t=3}

Learn more:

brainly.com/question/20845315

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a regular polygon has a perimeter of 36 inches. each side is exactly 6 inches long. which figure does this discribe?
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