(f.g)(x) = f (g(x))= f ( x^4+3)
= (x^4+3)^2 + 2 ( x^4+3) - 6
= x^8 + 9 + 6x^4 + 2x^4 + 6-6
= x^8 + 8x^4+9
Answer:
25 ft
Step-by-step explanation:
c = √a^2 + b^2 = √20^2 + 15^2 = 25ft
Hooke me up with a 5 star and a thanks :)
We can find the length of the ladder by squaring the known digits, adding them, and finding the square root of the sum. This would mean our first equation, after squaring, will look like this:
49+81=130
Now that we have <em>c</em> squared, we can go through and find the approximate square root, which is 11.4. That would mean the ladder is 11.4 meters long.
Let the speed of the boat be x
so going against the current the speed is x-7
going with the current the speed is x+7
let the distance be d
time = distance / speed
time to go against the current = d/(x-7)
time to go with the current = d/(x+7)
time going against the current is 3 times going <span>with the current
</span>
d/(x-7) = 3d/(x+7)
⇒⇒⇒ divide by d
1/(x-7)
= 3/(x+7)
x+7
= 3(x-7)
x+7 = 3x - 21
2x = 28
x = 14
So, the speed of the boat in still water is = 14 mph
Combine like terms:
11u+4v
