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goldenfox [79]
3 years ago
10

Can some one help me im confused

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
What ones do u need to be answered?then i can help u im sure :) <span />
LekaFEV [45]3 years ago
4 0
1) first one....90-27=63°
2)180-128=52°>>>>that is B
3)first one is suppliment....so A
4)180-125=55°....I think D....but not in pic !!!

so...go for it !!!
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What is 12 and 5/25 as a mixed number in simplest form?
KonstantinChe [14]
To start off, 5/25 is 1/5. 25 and 5 can both be divided by 5, thus it is 1/5 smiplified. Now you add 12 and it is 12 and 1/5.
5 0
3 years ago
Marcella's house cost $120 000. she paid 20 percent down payment and then borrowed the rest at 6.5 percent for 20 years. if she
chubhunter [2.5K]

Answer:

20% of 120,000 is 24,000 so 120,000-24,000 is 96,000

Now if she pays 7.46 for every 1000 she will have to repay 716.16 over 20 years.

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
If Amelia would like to double her money in twelve years, how much interest does she need to earn? 6 percent 12 percent 10 perce
sveticcg [70]
We can assign the value "2x" as the amount of money that Amelia which to achieve in twelve years.
So, his initial money is X.
We can try each percent to test if it could double the amount in 12 years.
x+0.06*12years*x=1.72X
x+0.12*12*x=1.44x
x+0.1*12*x=2.2x
x+0.166*12*x=2.992x

Therefore, the answer is 10 percent.
4 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
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