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svetlana [45]
3 years ago
6

75% rose comb 25% single comb

Biology
1 answer:
guapka [62]3 years ago
3 0

Answer:

given,

rose combed rooster (R)  ×  single combed hen (r)  

                                     RR × rr

                                          ↓

in F1 generation, all the chicks will be Rr

                                           ↓

in F2 generation, mating was done among their own group of Rr  

          Rr × Rr

               ↓

25% of RR   50% of Rr  and 25% of rr

phenotypes of chicks in f2 generation =  3:1 ( 75% rose combed as R is dominant and 25% single combed)

genotype = 1:2:1 ( 1/4 homozygous rose comb [RR] : 2/4 heterozygous rose comb [Rr] :1/4 homozygous single comb [rr])

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