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Eddi Din [679]
4 years ago
6

Solve the proportion below. 7/x=19

Mathematics
1 answer:
alexgriva [62]4 years ago
6 0

Answer:

The value of x is approximately 0.3684.

Step-by-step explanation:

Given:

\frac{7}x}=19

We need to solve the proportion.

Solution:

Now we can see that;

In given equation one number is fraction and other number is whole number.

Now To make whole number into fraction we will divide by 1.

hence the whole number will be equal to;

19=\frac{19}{1}

Now the new equation will be;

\frac{7}{x}=\frac{19}{1}

Now by cross multiplication we get;

7\times1=19\times x\\\\7=19x

Now dividing both side by 19 we get;

\frac{7}{19}=\frac{19x}{19}\\\\x\approx0.3684

Hence the value of x is approximately 0.3684.

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Hey there!

3x+6y=12

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Mr. Ivey teaches dance at the middle school. His classes are 90 minutes long, and he spends 94% of class time teaching strength
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84.6 minutes

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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar
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Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ​ounces, with a sample standard deviation of 0.052 ounces.

Let \mu = <u><em>population mean amount packaged. </em></u>

So, Null Hypothesis, H_0 : \mu = 8.17 ounces    {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, H_A : \mu\neq 8.17 ounces    {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample mean amount dispensed = 8.171 ounces

             s = sample standard deviation = 0.052 ounces

            n = sample of packages = 50

So, <u><em>the test statistics</em></u> =  \frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }  ~   t_4_9

                                    =  0.1359  

The value of t-test statistics is 0.1359.

<u>Also, the P-value of test-statistics is given by;</u>

the meaning of the​ p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

                    P-value = P( t_4_9 > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

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