Answer:
12 presents
Step-by-step explanation:
4/6= 2/3
2/3 x 18 = 12
Answer:
sum of 22nd = 1,428.05
sum of 23 to 40 is 932.53
Step-by-step explanation:
A(n)=20(1.1)^n-1
20 is the first term or a1
1.1 is the common ratio or r
A(22) = 20(1.1)^22-1
22nd term = 20(1.1)^21
22nd term = 148.00
sum of geometric sequence
formula
Sn = a1(1-r^n)/1-r
Sn = sum
a1 = first term
n = number of term
r = constant ratio
sum of 22nd = 1,428.05.
23 to 40 is 17 terms
Sequence: 23, 25.3, 27.83, 30.613, 33.6743, 37.04173, 40.745903 ...
The 17th term: 105.684378686
Sum of the first 17 terms: 932.528165548
socratic
miniwebtoolcomgeometricsequencecalculator
Answer:
Step-by-step explanation:
3 (5+1) divided by 3 to the second power = 2
8 divided by 4 times 2 = 4
7 + 2.4 = 9.4
i hope this helps god bless
Answer:
15/13
Step-by-step explanation:
hope that helps thanks for ur questions
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Answer:</h2>
<h2>
Step-by-step explanation:</h2>
a. 2x^-3 • 4x^2
To solve this using only positive exponents, follow these steps:
i. Rewrite the expression in a clearer form
2x⁻³ . 4x²
ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.
In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to positive as follows;
iii. We then solve the result as follows;
=
Therefore, 2x⁻³ . 4x² =
b. 2x^4 • 4x^-3
i. Rewrite as follows;
2x⁴ . 4x⁻³
ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.
iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;
Therefore, 2x⁴ . 4x⁻³ =
c. 2x^3y^-3 • 2x
i. Rewrite as follows;
2x³y⁻³ . 2x
ii. Change position of terms with negative exponents;
iii. Now solve;
Therefore, 2x³y⁻³ . 2x =