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3 years ago

Which is equivalent to 3x-4y=8

Mathematics

1 answer:

Alika [10]3 years ago

8 0

Answer:

The answer is D) Y = 3/4x-2

Step by step explanation:

3x - 4y = 8

Express it in the term of y.

Subtract 3x from both sides:

3x - 4y - 3x = 8 - 3x

- 4y = 8 - 3x

Divide both sides by -4

-4y/-4 = (8 - 3x)-4

y = 8/-4 - 3x/-4

y = -2 - (-3/4x)

y = -2 + 3/4x

y = 3/4x - 2

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Question 5 of 10

musickatia [10]

Answer:

25 in ^2

Step-by-step explanation:

First find the area of the circle

A = pi r^2

A = 3.14 ( 4.3)^2

A =58.0586

The take the fraction of the circle that is shaded

A circle is 360 degrees

155/360

155 /360 * the total area = area shaded

31/72 * 58.0586 = 24.99745278 in ^2

Rounding yields 25 in ^2

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3 years ago

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610 divided by 20 without a decimal

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Answer:31 or 30.5 orrr 61/2

Step-by-step explanation:

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tensa zangetsu [6.8K]

Answer:

b and d

Step-by-step explanation:

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3 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago

Factor the trinomial: 4x2 - 8x - 5

shtirl [24]

Correct answer is A.

$(2x + 1)(2x - 5)
\\2x(2x-5)+1(2x-5)
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\\4x^2-x-5$

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