All categories

2 years ago

Estimate the sum by rounding each number to the nearest hundred first

Mathematics

1 answer:

Natasha2012 [34]2 years ago

4 0

500+600+900+400+600= 3000

You might be interested in

If h has an inverse funtion and h^-1 (4) = 2 , find h(-2)<br><br> Please help Thanks!

mestny [16]

You're given that $h^{-1}(4)=2$ , which means $h(2)=4$ . But this tells you nothing about $h(-2)$ ...

3 0

2 years ago

If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation? A) 1 B) 10 C) 10.8 D)

Anit [1.1K]

$\bf \begin{array}{cccccclllll}&\\
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&\\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&\\
y&=&{{ k}}&\cdot&x&\\
&\\
&& y={{ k }}x&\\
\end{array}& \\\\\\
\textit{we know that }
\begin{cases}
y=12\\
x=1.2
\end{cases}\implies y=kx\implies 12=k\cdot 1.2$

solve for "k" to find "k", or the "constant of variation"

6 0

3 years ago

Read 2 more answers

Evaluate the expression

Scilla [17]

Answer:

Step-by-step explanation:

substitute the values that are given into the expression.

c + a = x

12 + 3 = x

15 = x

6 0

2 years ago

Read 2 more answers

Find the equality represented by the graph?

Talja [164]

Answer:

$-x+4y$

Step-by-step explanation:

Given: graph

To find:the inequality

Solution:

Equation of a line passing through points $(x_1,y_1),(x_2,y_2)$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Take $(x_1,y_1)=(0,3),(x_2,y_2)=(4,4)$

So,equation of line is evaluated as follows:

$y-3=\frac{4-3}{4-0}(x-0)\\ y-3=\frac{x}{4}\\ 4y-12=x\\-x+4y=12$

As per the graph,inequality is $-x+4y$

Here, use sign < and not $\leq$ as line in the graph is dotted that is points on the line are excluded.

4 0

2 years ago

Please help, I don’t know how to do this. Use a compass and straightedge to construct a line perpendicular to the given through

Tasya [4]

Step-by-step explanation: B

put the center of the circle on the right of the line and the edge of the circle on the p. Make part of a circle. you dont have to do the whole circle, but you can if you want.

do the same thing again but on the other side of the line.

now it should look like the first image i included (if you didnt do the whole circle)

now take your straightedge/ruler/line maker and make it go through the intersecting points on the circles, like the second image.

Note that my images are for demonstration. They're not perfect at all, they're just to show you how to do it.

5 0

2 years ago