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andriy [413]
3 years ago
11

The diagram shows a rectangle.

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

42cm²

Step-by-step explanation:

It is actually 7cm by 6cm

You are taking 2 x 0.5cm  of the smaller sides rectangles which is 1. This leaves us with 6 x 7 = 42cm²

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What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11
Scrat [10]

Try 122.

<h3 />

Step-by-step explanation:

Since <em>x</em> = 1, x^6 = 1.

Since <em>y</em> = 11, 11^2 = 121.

1 + 121 = 122.

<h3 /><h3>So, the value of <em>x</em> ^ 6 + <em>y </em>^ 2 = 122.</h3><h3 />
8 0
2 years ago
Read 2 more answers
50 POINTS PLEASE HELP!!!!!!!!!! ALL SH!+Y ANSWERS REPORTED.
NNADVOKAT [17]
62=14 + 2x

62-14=2x

48=2x

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6 0
3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
3 years ago
Ignore “c”. i need help with 5 and 6. i suck at this lol. brainliest for whoever gives best answer
34kurt

Answer:

5 = 1/3

6 A = 24%

6 C = 26%

Step-by-step explanation:

sorry if its wrong i didn't have a lot of time

6 0
2 years ago
Please help meeeeeee​
nika2105 [10]
The slope would be -1/3 therefore your point would be at (-12,0) and (0,-4)
5 0
2 years ago
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