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Luba_88 [7]
3 years ago
5

A metal pipe is 33 3 /4 inches long. If you cut the pipe into pieces that are each 3 3 /4 inches long, how many total pieces wil

l you have?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
3 3/4 = 15/4

We have to deal with each rod since they are not combined.

24/(15/4) = 24(4/15) = 32/5 = 6 2/5

The 2/5 is waste.

6(32) = 192 pieces
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Answer: 2n + 1 = n + 11

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Grade 10 quick maffs pls help
kolezko [41]
You’re answer would be B (-6, 1) (-1, -1)
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A box contains two purple marbles nine orange marbles and seven yellow marbles if you pick two without looking what is the proba
maw [93]

Answer:

1/4

Step-by-step explanation:

First, add up the marbles:

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Multiply by 2 because you pick two:

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Hope this helped.

8 0
2 years ago
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Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

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Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

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Degree of freedom = n1+n2-2 = 12+12-2 = 22

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Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

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3 years ago
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