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3 years ago

Please need help I will be MARKING as BRIANILIST, thank you so much.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

Here is the mpg for each 6 cylinder:

(23), (24), (30), (23) ,(21), (20) ,(23), (21) ,(23), (22)

i : between 20-24 = 9/10

ii between 25-29 = 0/10

iii at least 30 mpg = 1/10

c- 38, 28,25,26,24,25

d- the mileage of six cylinder car is less than the mileage of four cylinder cars using the same amount of fuel. it is somehow accurate, other factor that affects is the model of the car and how big it is.

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Write this number in expanded form.4,508,227

Semmy [17]

4000000+500000+8000+200+20+7

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3 years ago

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Does 514, 684, 855 make a right triangle

Naily [24]

Answer:

No, it does not.

Step-by-step explanation:

This does not make a right triangle because in order to have a right triangle you must have 2 of the same numbers.

For example:

900, 800, 900 makes a right triangle

900, 800, 700 does not.

Hope this helped :D

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3 years ago

Veronica Foaley sells evening jackets sewn with metallic threads and beads. She wants to set a price of $600 for a jacket. The m

boyakko [2]

The most she can pay for the jacket is $375 (=600/(100%+60%)) assuming this is the cost of the jacket before it sewn with metallic threads and beads. A markup is a difference between the production cost and the selling price in order to cover the additional cost related to the product. Based on the data, she wants to keep the 60% for covering the cost.

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3 years ago

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A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

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3 years ago

Simplify the rational expression by rationalizing the denominator √15/√6x

noname [10]

Answer:

√10/2x

Step-by-step explanation:

Multiply by √6 on the top and bottom to rationalize the denominator.

(√15×√6)/(√6x×√6) = √90/6x = (√9×√10)/6x = 3√10/6x = √10/2x

4 0

3 years ago

Please need help I will be MARKING as BRIANILIST, thank you so much. ​

Please need help I will be MARKING as BRIANILIST, thank you so much.