The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
<u>Step-by-step explanation:</u>
Let the speed of wind and speed of plane in still air are w and p km/h respectively.
The effective speed on onward journey was
................(1)
The effective speed on return journey was
..............(2)
Adding equation (1) and equation (2) we get,
⇒
⇒
⇒
Putting value of in we get:
⇒
⇒
⇒
Therefore ,The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
Answer:
C. y = x² - 6x + 10
Step-by-step explanation:
Formula f(x)=a(x-h)^2+k (h,k) is vertex
Y=a (x-3)^2+1
Plug in y intercept
10=a (0-3)2+1
10=-3^2a+1
10=9a+1
9=9a
A=1
Y=(x-3)2 +1
Y=x2-6x+9+1
Y=x2-6x+10
brainly.com/question/3584775#citedsource
Answer:
$20.16
Step-by-step explanation:
First we need to find 12% of his current hourly rate, 12% is our decimal multiplier here so we use 0.12. In order to get 12% we need to multiply our decimal by $18 which is:
$18 × 0.12 = $2.16
Now let's add this 12% on top of his current hourly rate.
$18 + $2.16 = $20.16
And that's the final answer.