The 4 m board's center of mass is 2 m so the pivot point is somewhere between Tasha and 2 m (if you draw a picture it's going to make this clearer)
The mass of Tasha * her distance from the pivot point = the board's mass * distance from the pivot point.
<span> Let d1 be the distance Tasha is from the pivot point. The board's center of mass from the pivot point is 2 m - d1
</span><span> 20 kg * d1 = 10 kg * (2m - d1)
</span><span> Solve for d1, you should get 2/3 of a m for the distance Tasha is from the pivot or support point. The center of mass for the board is 1 1/3 m from the support point. </span>
Answer:
a = 2.5 m/s^2
Explanation:
u = 0
v = 25
t = 10
(using first eq. of motion)
a = (v - u) /t
a = (25 - 0) /10
a = 25/10
a = 2.5 m/s^2
Answer:
the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person in cart, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
acceleration due to gravity, g = 9.8 m/s²
final speed of the cart before it goes up the hill, v = 19 m/s
Apply the principle of conservation of energy;

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
Answer:
They are in free-fall motion.
Explanation:
The Earth orbiting astronauts are falling at an acceleration that is the same or greater than the acceleration due to gravity i.e., 9.81 m/s². If you are continuously falling at this rate then you will feel weightless.
This same effect is felt while going down in an elevator. When you down in an elevator you feel that you are lighter and feel that something is pushing you up. Earth-orbiting astronauts feel the same effect but the accelration is greater hence they feel weightless.
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m =
h '=
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.