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MissTica
3 years ago
10

A student is wearing a pair of sunglasses designed to reduce the glare from reflected surfaces. When the student tilts her head

to the side and back again, she notices that the brightness of the blue sky changes in intensity.
The student wonders why the intensity is affected by the orientation of her sunglasses. The light coming from the sky toward her sunglasses has most likely undergone

A. absorption
B. diffraction
C. polarization
D. refraction
Physics
1 answer:
agasfer [191]3 years ago
6 0
The answer is polarization. It is just like when you are on a boat and use polarized glasses so the water wont reflect into your eyes it also intensifies the color of the water so you can see better into the water.
example: you cant see any fish because glare from the sun, put on polarized glasses and now you can see fish up to 30 feet deep.
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Question 3 of 10
Morgarella [4.7K]

Answer:   Option C

 

Magnetic energy  |  Electromagnetic energy

7 0
3 years ago
A 5.73 kg bowling ball moves in a straight line at 1.6 m/s.
Schach [20]

Answer: 2546.66 m/s

Explanation:

We have the following data:

m_{1}=5.73 kg is the mass of the bowling ball

V_{1}=1.6m/s is the velocity of the bowling ball

m_{2}=3.6 g \frac{1 kg}{1000 g}=0.0036 kg is the mass of the ping-pong ball

V_{2} is the velocity of the ping-pong ball

Now, the momentum p_{1} of the bowling ball is:

p_{1}=m_{1}V_{1} (1)

p_{1}=(5.73 kg)(1.6m/s)

p_{1}=9.168 kg m/s (2)

And the momentum p_{2} of the ping-pong ball is:

p_{2}=m_{2}V_{2} (3)

If the momentum of the bowling ball is equal to the momentum of the ping-pong ball:

p_{1}=p_{2} (4)

m_{1}V_{1}=m_{2}V_{2} (5)

Isolating V_{2}:

V_{2}=\frac{m_{1}V_{1}}{m_{2}} (6)

V_{2}=\frac{9.168 kg m/s}{0.0036 kg} (7)

Finally:

V_{2}=2546.66 m/s

8 0
3 years ago
If you hit a ball with double the force, what will it do to the acceleration of the ball?
iVinArrow [24]

Answer:

If the force is doubled, then the acceleration would also double since F-net = ma. In this case, the acceleration would be 1 m/s per second.

7 0
3 years ago
How much force is required to drag a 90 lb. box up this "frictionless" inclined plane? 109 lb. 10 lb. 81 lb. 9 lb.
MrRissso [65]
I believe is 10 lb if not it's 9 lb.
5 0
3 years ago
Read 2 more answers
A frictionless circular ring 1.00 m in diameter is placed flat on the floor, and a 100-g ball is sent around its inside surface
VashaNatasha [74]

Answer:

 \Delta =2.88\times 10^{-2} J

Explanation:

given,

diameter of the ring = 1 m

radius = 0.5 m

mass of the ball = 100 g = 0.1 Kg

initial speed of the ball = 1.85 m/s

converted energy = change in kinetic energy

 \Delta = \dfrac{1}{2}m(v_f^2-v_i^2)

 \Delta = \dfrac{1}{2}\times 0.1 \times (2^2 - 1.85^2)

 \Delta = \dfrac{1}{2}\times 0.1 \times (2^2 - 1.85^2)

 \Delta = 0.0288 J

 \Delta =2.88\times 10^{-2} J

7 0
3 years ago
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