Answer:
Explanation:
given,
velocity of particle 1 = 0.741 c to left
velocity of second particle = 0.543 c to right
relative velocity between the particle = ?
for the relative velocity calculation we have formula
u_x = 0.543 c
v_x = - 0.741 c
Relative velocity of the particle is
Answer:
A.) 8 m/s
B.) 7.0 m
Explanation:
Given that a block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane.
(a) What is its velocity when it reaches the top of the plane?
Since the plane is frictionless, the final velocity V will be the same as 8 m/s
The velocity will be 8 m/s as it reaches the top of the plane.
(b) How far horizontally does it land after it leaves the plane?
For frictionless plane,
a = gsinø
Acceleration a = 9.8sin28
Acceleration a = 4.6 m/s^2
Using the third equation of motion
V^2 = U^2 - 2as
Substitute the a and the U into the equation. Where V = 0
0 = 8^2 - 2 × 4.6 × S
9.2S = 64
S = 64/9.2
S = 6.956 m
S = 7.0 m
<span>The primary gases of the atmosphere are _____:
</span>
nitrogen, oxygen, and carbondioxide
Answer:
d = 3.8857 g/cm^3
Explain:
Formula/: d = m/V
Hope this helps!
(a brainliest would be appreciated)
Answer:
Cosmic ray's frame of reference: 99,875 years
Stationary frame of reference: 501,891 years
Explanation:
First of all, we convert the distance from parsec into metres:
The speed of the cosmic ray is
where
is the speed of light. Substituting,
And so, the time taken to complete the journey in the cosmic's ray frame of reference (called proper time) is:
Converting into years,
Instead, the time elapsed in the stationary frame of reference is given by Lorentz transformation:
And substituting v = 0.98c, we find:
