The total work done by the electric field on the charge is given by the scalar product between the electric force acting on the charge and the displacement of the charge:
![W=F d cos \theta](https://tex.z-dn.net/?f=W%3DF%20d%20cos%20%5Ctheta)
where the force is F=qE, d=0.556 and
![\theta=55.2^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D55.2%5E%7B%5Ccirc%7D)
. Using the value of q and E given by the problem, we find
I am walking to the end of the room holding three textbooks.
Playing tug of war
Moving boxes to move out of your house
<h2>When Transferring Flammable Liquids - Option A</h2>
To create a pathway for the liquid to flow easily is a correct reason to physically connect objects with a bond wire when transferring flammable liquids. Physically connect the two conductive objects together with a bond wire to eliminate a difference in static charge potential among them. The bond wire is attached between the containers in the process of flammable filling liquid actions except for a metallic path is found.
Their are two coefficients of friction, static and kinetic, regardless, they have basically the same formula:
u*N = F... aka
coefficient of friction*normal force = force of friction
Hope that helps!