A proton traveling due north enters a region that contains both a magnetic field and an electric field. The electric field lines
1 answer:
You might be interested in
Answer:
Before start of slide velocity will be 14.81 m/sec
Explanation:
We have given coefficient of static friction
Angle of inclination is equal to
Radius is given r = 28 m
Acceleration due to gravity
We know that
So before start of slide velocity will be 14.81 m/sec
Answer:
0.423m
Explanation:
Conversion to metric unit
d = 4.8 cm = 0.048m
Let water density be
Let gravitational acceleration g = 9.8 m/s2
Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.
Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:
Where N is the spring force,
is the buoyancy force, which equals to the weight
of the water displaced by the submerged portion of the cylinder, which is the product of water density
, submerged volume
and gravitational constant g. W = mg is the weight of the metal cylinder.
The submerged volume would be the product of cross-section area and the submerged length x
Plug that into our force equation and we have