Answer:
6 gallons per minute
Step-by-step explanation:
Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is
Q = a + bt ........... (1)
Now, Q(t = 0) is given to be 50 gallons.
So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).
Now, two points on the graph are (0,50) and (1,44).
So, the slope = b = = - 6 gallons per minute.
Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)
Answer:
Slope AB = -3/2
R = (4, -7)
Step-by-step explanation:
AB (-6 , 8) and (-2 , 2)
Slope AB = (8 - 2) /(-6 + 2) = 6/-4 = -3/2
Triangle QRS , QR is half of AB, same orientation and given Q (2 , -4) so R = (4, -7)
Answer:
a) ∠2 and ∠4 are a linear pair
∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
∠7 = 65°
c) ∠2 and ∠3 are vertical angles
∠3 = 65°
Step-by-step explanation:
Linear pair : a pair of adjacent angles formed when two lines intersect. The two angles of a linear pair are always supplementary (two angles whose measures add up to 180°)
Alternate exterior angles : when two parallel lines are cut by a transversal (a line that intersects two or more other, often parallel, lines), the resulting alternate exterior angles are <u>congruent</u>.
Vertical angles : a pair of opposite angles formed by intersecting lines. Vertical angles are always <u>congruent.</u>
a) ∠2 and ∠4 are a linear pair
⇒ ∠2 +∠4 = 180
⇒ 65 + ∠4 = 180
⇒ ∠4 = 180 - 65
⇒ ∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
⇒ ∠2 ≅ ∠7
⇒ ∠7 = 65°
c) ∠2 and ∠3 are vertical angles
⇒ ∠2 ≅ ∠3
⇒ ∠3 = 65°
Answer:
The absolute maximum and the absolute minimum are (0, 16) and (2, 0).
Step-by-step explanation:
First, we obtain the first and second derivatives of the function by chain rule and derivative for a power function, that is:
First derivative
Second derivative
Then, we proceed to do the First and Second Derivative Tests:
First Derivative Test
Second Derivative Test
The Second Derivative Test is unable to determine the nature of the critical values.
Then, we plot the function with the help of a graphing tool. The absolute maximum and the absolute minimum are (0, 16) and (2, 0).
