Answer:
population = 600
heterozygotes = 2pq
The homozygous recessive percentage = 
q = 0.1
Solve for q:
∴ q = 
∴ q = 
∴ q = 0.316
solve for p:
for p + q = 1,
thus p = 1 – q = 1 – 0.316 = 0.684
The heterozygotes = 2pq
2pq = 2 x 0.316 x 0.684 = 0.432
600 x 0.432 = 259.2 = 259
so, the population reaches Hardy Weinberg equilibrium, 259 of indviduals should be heterozygous for this trait.
Hence, the correct answer is 259
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Oceanic crust<span>tends to be denser and thinner than </span>continental crust<span>, so the denser </span>oceanic crust<span> gets bent and pulled under, or subducted, beneath the lighter and thicker </span>continental crust<span>. This forms what is called a subduction zone. The answer is B.</span>
One/two child policy in China
Bacteria and Archaea Bacteria.