F(x) = log8^x = xlog8 - it's a linear function
TRUE
A. It is Increasing because a = log8 > 0
Answer:
B. 3x+1
Step-by-step explanation:
(3x+3)+(2x+1)+(4x+2)=9x+6
(12x+7)-(9x+6)=3x+1
Answer:
17
Step-by-step explanation:
3 + 7 * 6 / 3
PEMDAS says we multiply and add before adding and subtracting so we multiply first (going from left to right)
3 + 42 / 3
Then we divide
3 + 14 = 17
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
(5,2) because of the cordainte plane x axais is down and its positive so you get 5,2
