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3 years ago

Evaluate the algebraic expression 1.5t -7.2 for each given value 6 -5

Mathematics

1 answer:

Softa [21]3 years ago

7 0

Answer:

1.8 ; - 14.7

Step-by-step explanation:

Evaluate the algebraic expression 1.5t -7.2 for each given value 6 ; -5

For each of values 6 and - 5 ;

Substitute the values for t in the expression ; 1.5t - 7.2

Substituting 6 for t:

1.5(6) - 7.2

9 - 7.2

= 1.8

Substituting -5 for t:

1.5(-5) - 7.2

-7.5 - 7.2

= - 14.7

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A movie ticket costs $7. How much do six movie tickets cost?

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Read 2 more answers

A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab

ahrayia [7]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that $0 \le x \le 8 \:and\: $0 \le y \le 4$.$

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: $x + y \le 4$ ) are:

$(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)$

n(A)=15

Therefore:

$P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}$

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4 years ago

Find the exact circumference of a circle with the given radius.<br> 36 inches

-BARSIC- [3]

<span>its gonna be 2 times 3.14 times 36 and that would give me 226.08</span>

8 0

4 years ago

B. Determine the values of a and b so that f is continuous

miskamm [114]

Answer:

Step-by-step explanation:

For a function to be continuous

The right hand limit f'+(x) must be equal to the left hand limit f'-(x)

The right hand limit exist at where x>3

The resulting function is. x²+a

If x = 3

f'+(3) = 3²+a

f'+(3) = 9+a

For the left hand limit, this exist where

bx+a

f'-(x) =bx+a

f'-(3) = 3b+a

Since f'+(3) = f'-(3)

9+a = 3b+a

9 =3b

b = 9/3

b = 3

At the end point x = -3

For the left hand limit

f-(x)= √-b-x

f-(-3) = √-b-(-3)

f(-3) = √-b+3

For the right hand, the function is bx+a

f'+(x) = bx+a

f+(-3) = -3b + a

Equate both limits

√-b+3 = -3b+a

√-3+3 = -3(3)+a

0 = -9+a

a= 9

Hence a = 9 and b = 3

7 0

3 years ago