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svlad2 [7]
3 years ago
10

Write this number in two ways in expanded form 204.032

Mathematics
2 answers:
LenaWriter [7]3 years ago
6 0
200.000+4.000+30+2

(200.000X1)+(4.000X1
(30X1)+(2X1)
olga_2 [115]3 years ago
4 0

Expanded Numbers Form:

200
+ 0
+ 4
+ 0.0
+ 0.03
+ 0.002

Expanded Factors Form:

2 × 100
+ 0 × 10
+ 4 × 1
+ 0 × 0.1
+ 3 × 0.01
+ 2 × 0.001

Expanded Exponential Form:

2 × 102
+ 0 × 101
+ 4 × 100
+ 0 × 10-1
+ 3 × 10-2
+ 2 × 10-3
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To purchase $12,900 worth of machinery for her business, Melissa made a down payment of $2100 and took out a business loan for t
Ierofanga [76]

Answer:

a) $13588.08

b) $688.08

Step-by-step explanation:

Melissa had to purchase $12,900 worth of machinery for her business.

She made a down payment of $2100 and after that made monthly payments of $478.67 for the business loan for the rest.

Given that after years of paying monthly payments of $478.67, she finally paid off the loan.

Assume that she took 2 years to repay the loan.

a) Therefore, the total amount Melissa ended up paying for the machinery was $[2100 + (478.67 × 24)] = $13588.08 (Answer)

b) Therefore, the amount of interest that Melissa pay on the loan is $(13588.08 - 12900) =$688.08. (Answer)

4 0
3 years ago
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dolphi86 [110]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Alona [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
What is the area of this compound shape?!
iris [78.8K]
So you would start with the square and do 18 times 18 which equals 324 then for the triangle it's base times height divided by two so 9 times 18 divided by 2 which equals 81 then you add the triangle plus the square and your final answer is

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In the third degree polynomial function f(x) =x^3 + 4x, why are 2i and -2i zeros?
IgorC [24]

Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since i^2=-1, then i^3=i^2i=-i, and we can apply this when we evaluate f(x) =x^3 + 4x for 2i and -2i.

First we have:

f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0

Which shows that 2i is a zero of f(x).

Then we have:

f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0

Which shows that -2i is a zero of f(x).

4 0
4 years ago
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