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3 years ago

What happens to the molecules when a gas is compressed?

Physics

2 answers:

timama [110]3 years ago

6 0

Answer:

B. There is a drop in temperature

C. increases when pressure decreases

Explanation:

With constant pressure, the volume is proportional to the temperature. Since the temperature is directly related to the average kinetic energy of the gas molecules. So, the lower the volume (compression), the lower the speed of the molecules (temperature).

On the other hand. With constant temperature, when the pressure increases, the volume drops, while if the pressure decreases the volume increases.

gulaghasi [49]3 years ago

5 0

The first answer is c the second answer would be d

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If your car was traveling at 60 mph, that is about 27m/s. How long would it take a car traveling at 27m/s to slow to a stop, if

RUDIKE [14]

Answer:

vf=at+v0. vf=0

-v0=at

t=-v0/a=(-27m/s)/(-8m/s^2)=3.4s

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3 years ago

The image shows a pendulum that is released from rest at point A. Which energy transformation is correct? From A to C, kinetic e

irakobra [83]

Answer:

From C to D, kinetic energy is transformed into gravitational potential energy.

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3 years ago

Read 2 more answers

A huge cannon is assembled on an airless planet (ignore any effects due to the planet's rotation). The planet has a radius of 5.

Ganezh [65]

Answer:

The projectile's speed as it passes the satellite is 1497.8 m/s.

Explanation:

Given that,

Radius of planet $r=5.00\times10^{6}\ m$

Mass of planet $m=3.95\times10^{23}\ kg$

Speed = 2000 m/s

Height = 1000 km

We need to calculate the projectile's speed as it passes the satellite

Using conservation of energy

$E_{1}=E_{2}$

$\dfrac{1}{2}mv_{1}^2+\dfrac{GmM}{r_{1}}=\dfrac{1}{2}mv_{2}^2+\dfrac{GmM}{R+h}$

$\dfrac{v_{1}^2}{2}+\dfrac{GM}{r_{1}}=\dfrac{v_{2}^2}{2}+\dfrac{GM}{R+h}$

$-\dfrac{v_{2}^2}{2}=-(\dfrac{GM}{R}-\dfrac{GM}{R+h}-\dfrac{v_{1}^2}{2})$

$v_{2}^2=v_{1}^2+2GM(\dfrac{1}{R+h}-\dfrac{1}{R})$

$v_{2}=\sqrt{v_{1}^2+2GM(\dfrac{1}{R+h}-\dfrac{1}{R})}$

Put the value into the formula

$v_{2}=\sqrt{2000^2+2\times6.67\times10^{-11}\times3.95\times10^{23}(\dfrac{1}{5.00\times10^{6}+1000\times10^{3}}-\dfrac{1}{5.00\times10^{6}})}$

$v_{2}=1497.8\ m/s$

Hence, The projectile's speed as it passes the satellite is 1497.8 m/s.

4 0

4 years ago

BRAINLYIST ASAPPP write and claim evidence and reasoning statement that explains why mercury and Venus do not have any moons

umka2103 [35]

answer:They are too close to the sun!

Explanation:Because Mercury is so close to the Sun and its gravity, it wouldn't be able to hold on to its own moon. Any moon would most likely crash into Mercury or maybe go into orbit around the Sun and eventually get pulled into it.Same with Venus!

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3 years ago

In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves wit

Minchanka [31]

Given :

Initial velocity , u = 0 m/s² .

To Find :

The acceleration of the cart.

Solution :

Since, acceleration is constant.

Using equation of motion :

$x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}$

Putting, t = 1 s and x = 4 m in above equation, we get :

$4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2$

Therefore, the acceleration of the cart is 8 m/s².

5 0

3 years ago