The answer is c: <span>1960 J
</span>Potential Energy :
<span>PE = m x g x h = 40*9.8*5=1960
</span>
The resistance of 2.5 m wire is 0.18 ohm.
Answer:
Option C.
Explanation:
Resistance is the measure of obstacle given to the flow of currrent. As per ohm's law, resistance is the constant of proportionality between voltage and current. But the resistance of each circuit depends upon the nature of resistor used in that circuit.
R =
So the resistance depends upon the resistivity of the material, length of the material and inversely proportional to the cross sectional area of the material.
In this case, the length of the wire is varied and the composition and cross section is kept constant. From the formula, it can be seen that resistance is directly proportional to the length of the resistor. So if the wire acting as resistor undergoes a decrease in length from 100 m to 2.5 m then there will be decrease in the resistance of the wire also.
Let be the resistance of 100 m wire and be the resistance of 2.5 m wire.
Then, , remaining all parameters will get canceled out due to the usage of same wire with same cross sectional area.
So,
So the resistance of 2.5 m wire is 0.18 ohm.
The answer is B. The wave is very long.
The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
<h3>
What are we to consider in equilibrium ?</h3>
Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = ( - ) / ( + )
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
Learn more about Equilibrium here: brainly.com/question/517289
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Your Answer Is D: Type One Diabetes. Hope That Helps!