The loudness level of a sound, D, in decibels, is given by the formula Upper D equals 10 log (10 Superscript 12 Baseline Upper
I )D=10log1012I, where I is the intensity of the sound, in watts per metersquared2. Decibel levels range from 0, a barely audible sound, to 160, a sound resulting in a ruptured eardrum. The sound of a certain animal can be heard 500 miles away, reaching an intensity of 2.62.6times×10 Superscript 6106 watts per meter squared .meter2. Determine the decibel level of this sound. At close range, can the sound of this animal rupture the human eardrum?
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Answer:
188.0 decibels
Explanation:
Substitute I = 6.3 x 10^6 into the given formula
D(6.3 x 10^6) = 10log(10^12 x 6.3 x 10^6) = 188.0 to one decimal place.
This is greater than 160 decibels, so the sound could rupture the human eardrum.
Substitute I = 6.3 x 10^6 into the given formula
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Answer:
Work done by the boy is 135 J and is positive work.
Friction is the force acting that stops the sled and her sister.
Work done by friction is negative work.
Explanation:
Given:
Force acting on the sled by the boy is,
Displacement of the sled in the direction of force is,
We know that, positive work is said to be done by a force, if the force causes displacement in its own direction. Also, negative work is said to be done by a force, if the force causes displacement in the direction exactly opposite to the direction of the applied force.
Here, the force applied by the boy causes a displacement in the direction of the applied force. So, work is positive and is given as:
Work = Force × Displacement
Therefore, the work done by the boy is positive and equal to 135 J.
Now, when the force of push is removed, then the body will experience only the frictional force in the opposite direction which eventually causes the sled to stop.
Here, the direction of force is backward while the displacement is in the forward direction. So, both of them are in opposite direction.
So, work done by frictional force is negative.