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klemol [59]
3 years ago
12

Triangle FEG is similar to triangle IHJ. Find the value of x. PLEASE ANSWER!!!!

Mathematics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

x=24

Step-by-step explanation:

60/45=36/x+3

4/3=36/x+3

108=4x+12

96=4x

x=24

gogolik [260]3 years ago
5 0

Answer:

24

Step-by-step explanation:

the triangle on the left has dimensions 1.25x greater than the one on the right, because the bottom side of the triangle measures 45 units, but it measures 60 on the right. knowing this you can find that the side length on the left of the right triangle is 27, so x + 3 must be 27. x=24

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Which is the solution of this system of equations? y=5x−83y=x+18<br><br> y+5(3)=15
Ulleksa [173]

Answer:

y=5x−83y=x+18    (the question is wrong; it has 2 equal signs)

y+5(3)=15

y+15=15   (multiply 5*3; you get 15)

y= 15-15

y= 0

7 0
3 years ago
One hiking club charges $16 to become a member and $3 to participate on each hike. Another club charges no membership fee, but c
yawa3891 [41]

Answer:

x < 8

Step-by-step explanation:

x= # of hikes

3x +16 =5x

-3x. -3x

16=2x

16/2= 8

2x/2= x

8=x

x=8

check:

3(8) +16 =5(8)

24 +16 =40

40=40 ✓

there for at 8 hikes with either deal it would be the same but if you went up a number of hikes for the first option it would only be $43.00 spent in total. but with the second option it would be $45.00.

7 0
3 years ago
Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).
svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}

<h3>Mid point is: (2.8;4.9)</h3>

7 0
3 years ago
Instructions: Determine whether the following polygons are similar. If yes, type in
Anni [7]

Answer:

No, the polygons aren't similar since they don't have a constant scale factor.

8 0
2 years ago
The boxed definition of absolute value states that |a|=-a if a is a negative number. Explain why |a| is always nonnegative, even
Temka [501]

Final answer:

Since absolute values determine the distance between the number and the value whether the value is positive or negative. As distance is always positive.

Thus, |a| is always nonnegative, even though |a|=-a for negative values of a.

Step-by-step explanation:

Step 1

It is said that |a| is always nonnegative even though even though |a|=-a for negative values of a.

Step 2

This is because by the definition of an absolute value, any real number inside an absolute value symbol || will always be positive.

7 0
2 years ago
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