Divide 3/4 by 1/8 and you should get 6 hurdles.
The answer to this question would be 0.14.
Hope this helps!
Comment if you have any questions!!!
Answer:
b
Step-by-step explanation:
Answer:
32![m^{2}/min](https://tex.z-dn.net/?f=m%5E%7B2%7D%2Fmin)
Step-by-step explanation:
We let the length of the square be l, the diagonal be z and the area be A.
Then by Pythagoras theorem;
![l^{2}+l^{2}=z^{2}\\2l^{2}=z^{2}](https://tex.z-dn.net/?f=l%5E%7B2%7D%2Bl%5E%7B2%7D%3Dz%5E%7B2%7D%5C%5C2l%5E%7B2%7D%3Dz%5E%7B2%7D)
The are of a square of length l is given as;
![A=l^{2}](https://tex.z-dn.net/?f=A%3Dl%5E%7B2%7D)
Combining these two equations yields;
![z^{2}=2A](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D2A)
![A=\frac{z^{2} }{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Bz%5E%7B2%7D%20%7D%7B2%7D)
Next, we have been given;
![\frac{dz}{dt}=8](https://tex.z-dn.net/?f=%5Cfrac%7Bdz%7D%7Bdt%7D%3D8)
We are required to find;
when z = 4
By chain rule;
![\frac{dA}{dt}=\frac{dA}{dz}*\frac{dz}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7BdA%7D%7Bdz%7D%2A%5Cfrac%7Bdz%7D%7Bdt%7D)
Differentiating
with respect to z yields;
![\frac{dA}{dz}=z](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdz%7D%3Dz)
Therefore,
= 8z
When z is 4m the area of the square will be increasing at a rate of;
8m/min * 4m = 32![m^{2}/min](https://tex.z-dn.net/?f=m%5E%7B2%7D%2Fmin)
Answer: - 2/5
Step-by-step explanation: Isolate the vcariable by divding each side by factors that don't contain the variable.
Exact Form: x = - 2/5
Deciaml form: x = -0.4
Hope this helps! :) ~Zane